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3 years ago

Helpp I just need the total of both

Mathematics

1 answer:

Fynjy0 [20]3 years ago

3 0

5 small cards ($12) and 3 large cards ($11.85) and the total of both ($12 + $11.85) = $23.85

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Which is the center of a circle whose equation is x2+y2+4x-8y+11=0?

Nikolay [14]

Answer:

Center (-2 , 4)

Step-by-step explanation:

x^2 + 4x + y^2 - 8y = - 11

(x^2 + 4x + (4/2)^2 + (y^2 - 8y + (8/2)^2 ) = - 11 + 4 + 16

(x + 2)^2 + (y - 4)^2 = 9

Center (-2, 4)

6 0

3 years ago

Which equation represents the graphed function

xxMikexx [17]

It’s easy just find the slope and the answer is gonna be obvious

Slope= y2-y1/x2-x1

Slope = -2-(-1)/0-4 = -1/-4 = 1/4

Slope = 1/4x

So the answer should be C

5 0

3 years ago

Can anyone please help me with these two been working on them and no clue

Lilit [14]

Answer:

360 cents

Step-by-step explanation:

Multiply 0.45 x 8. To get $3.6.

There are 360 cents in three dollars and sixty cents

8 0

3 years ago

Read 2 more answers

What is the value of x? x−1/6=8 Enter your answer in the box in simplest form.

Gnoma [55]

X = 8 16/99 is fraction form

3 0

3 years ago

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Create the linear equation from the points (3,3) and (1,-5).

Kisachek [45]

Answer:

$-4x + y = -9\:or\:y = 4x - 9$

Step-by-step explanation:

First, find the rate of change [slope]:

$\displaystyle \frac{-y_1 + y_2}{-x_1 + x_2} = m \\ \\ \frac{-3 - 5}{-3 + 1} = \frac{-8}{-2} = 4$

Then, plug these coordinates into the Slope-Intercept Formula instead of the Point-Slope Formula because you get it done much swiftly that way. It does not matter which ordered pair you choose::

−5 = 4 + b

$\displaystyle -9 = b \\ \\ y = 4x - 9$

If you want it in Standard Form:

y = 4x - 9

- 4x - 4x

_________

$\displaystyle -4x + y = -9$

_______________________________________________

3 = 4[3] + b

$\displaystyle -9 = b \\ \\ y = 4x - 9$

y = 4x - 9

- 4x - 4x

_________

$\displaystyle -4x + y = -9$

** You see? I told you it did not matter which ordered pair you choose because you will ALWAYS get the exact same result.

I am joyous to assist you anytime.

7 0

4 years ago