Division I'm pretty sure Try that
Answer:
1.C
2.A
3.D
4.C
5.B
6.A
7.B
8.C
9.A
10. D
Step-by-step explanation:
For Problem 1, the work is as follows:
![2(3x-1)+x\\Distribute\\6x-2+x\\7x-2](https://tex.z-dn.net/?f=2%283x-1%29%2Bx%5C%5CDistribute%5C%5C6x-2%2Bx%5C%5C7x-2)
For Problem 2, the work is as follows:
![(3x^{2} +6x+4) - (-x^{2} +2x-1)\\Distribute -\\(3x^{2} +6x+4) + (x^{2} -2x+1)\\Combine\\4x^{2} +4x+5](https://tex.z-dn.net/?f=%283x%5E%7B2%7D%20%2B6x%2B4%29%20-%20%28-x%5E%7B2%7D%20%2B2x-1%29%5C%5CDistribute%20-%5C%5C%283x%5E%7B2%7D%20%2B6x%2B4%29%20%2B%20%28x%5E%7B2%7D%20-2x%2B1%29%5C%5CCombine%5C%5C4x%5E%7B2%7D%20%2B4x%2B5)
For Problem 3, the work is as follows:
![5b-(a+c)^{2} \\5(3) - (-1+-4)^{2} \\15 - (-5)^{2} \\15-25\\-10](https://tex.z-dn.net/?f=5b-%28a%2Bc%29%5E%7B2%7D%20%5C%5C5%283%29%20-%20%28-1%2B-4%29%5E%7B2%7D%20%5C%5C15%20-%20%28-5%29%5E%7B2%7D%20%5C%5C15-25%5C%5C-10)
For Problem 4, the work is as follows:
![4x-8 = -12\\+8\\4x = -4\\-4/4 = -1\\x = -1](https://tex.z-dn.net/?f=4x-8%20%3D%20-12%5C%5C%2B8%5C%5C4x%20%3D%20-4%5C%5C-4%2F4%20%3D%20-1%5C%5Cx%20%3D%20-1)
For Problem 5, the work is as follows:
![\frac{1}{2} (12x-6) = 2x-15\\Distribute\\\\6x - 3 = 2x -15\\+3\\6x = 2x -12\\-2x\\4x = -12\\-12/4\\x = -3](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2812x-6%29%20%3D%202x-15%5C%5CDistribute%5C%5C%5C%5C6x%20-%203%20%3D%202x%20-15%5C%5C%2B3%5C%5C6x%20%3D%202x%20-12%5C%5C-2x%5C%5C4x%20%3D%20-12%5C%5C-12%2F4%5C%5Cx%20%3D%20-3)
For Problem 6, the work is as follows:
![17 *0.06 = 1.02\\17+1.02 = 18.02](https://tex.z-dn.net/?f=17%20%2A0.06%20%3D%201.02%5C%5C17%2B1.02%20%3D%2018.02)
For Problem 7, the work is as follows:
![x = (2,0)\\y = (0,-1)\\\frac{rise}{run} \\y = \frac{1}{2} x-1](https://tex.z-dn.net/?f=x%20%3D%20%282%2C0%29%5C%5Cy%20%3D%20%280%2C-1%29%5C%5C%5Cfrac%7Brise%7D%7Brun%7D%20%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20x-1)
For Problem 8, the work is as follows:
![y_{2} -y_{1} \\x_{2} -x_{1} \\-1-1 = -2\\0-(-2) = 2\\Slope = -1](https://tex.z-dn.net/?f=y_%7B2%7D%20-y_%7B1%7D%20%5C%5Cx_%7B2%7D%20-x_%7B1%7D%20%5C%5C-1-1%20%3D%20-2%5C%5C0-%28-2%29%20%3D%202%5C%5CSlope%20%3D%20-1)
For Problem 9, the work is as follows:
![3y - 2x +6 = 0\\-3y\\(-3y - -2x+6)/-3\\y = \frac{2}{3} x -2](https://tex.z-dn.net/?f=3y%20-%202x%20%2B6%20%3D%200%5C%5C-3y%5C%5C%28-3y%20-%20-2x%2B6%29%2F-3%5C%5Cy%20%3D%20%5Cfrac%7B2%7D%7B3%7D%20x%20-2)
For Problem 10, the work is as follows:
![(y-3) = -2(x-1)\\Distribute\\(y-3) = -2x+2\\+3\\y = -2x +5](https://tex.z-dn.net/?f=%28y-3%29%20%3D%20-2%28x-1%29%5C%5CDistribute%5C%5C%28y-3%29%20%3D%20-2x%2B2%5C%5C%2B3%5C%5Cy%20%3D%20-2x%20%2B5)
Hope this Helps!
Answer:
5/6, 5/8, 5/11, 5/19
Step-by-step explanation:
The larger the denominator, the smaller the sections
3 2/3 hours. Because if you do 2 3/4 times 1 1/3 you get 11/3 which simplifies into a mixed fraction of 3 2/3.
Answer:
The slope of the line must be 3
Step-by-step explanation:
<u><em>The picture of the question in the attached figure</em></u>
step 1
we know that
The volume of a rectangular prism is equal to
----> equation A
where
B is the area of the base of the prism
h is the height of the rectangular prism
step 2
The volume of a square pyramid is equal to
-----> equation B
where
B is the area of the square base of pyramid
h is the height of the pyramid
step 3
substitute equation A in equation B
![V_s_p=\frac{1}{3}V_r_p](https://tex.z-dn.net/?f=V_s_p%3D%5Cfrac%7B1%7D%7B3%7DV_r_p)
Find the relationship between the volume of a rectangular prism and the volume of a square pyramid
![\frac{V_r_p}{V_s_p}=3](https://tex.z-dn.net/?f=%5Cfrac%7BV_r_p%7D%7BV_s_p%7D%3D3)
therefore
The slope of the line must be 3
let's check it
To solve for the slope of the line, you must choose two coordinates first and use the formula
![m=\frac{y2-y1}{x2-x1}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By2-y1%7D%7Bx2-x1%7D)
Choosing the points (2,6) and (3,9)
substitute
----> is correct