Answer:
Horizontal distance is 142.12 feet.
Step-by-step explanation:
We have,
Velocity of the ball is 38.50 ft/sec. The angle of projection of the ball is 35 degrees.
It is required to find the horizontal distance covered by it before it comes back to the ground on its first bounce. It means we need to find the horizontal range of the projectile. Range of a projectile is given by :
So, the horizontal distance covered by it before it comes back to the ground on its first bounce is 142.12 feet.
Given that,
The camera sights the stadium at a 7 degree angle of depression.
The altitude of the blimp i slide 300 m.
To find,
The line of sight distance from the camera to the stadium.
Solution,
If we consider a right angled triangle. Let x is its hypotenuse i.e. the line of sight distance from the camera to the stadium. Using trigonometry :
So, the line of sight is at a distance of 2461.65 m from the camera to the stadium.
Answer:
35 <5m
35/5 < 5m/5
7 < m
m = 8,9,10,11,12,.......
a + 6 9
a + 6 - 6 9 -6
a 3
a = 3,4,5,6,7,......
8-g > 5
8 -g +g > 5 +g
8 > 5 +g
8 -5 > 5 -5 +g
3 > g
g =4,5,6,7,8.......
Step-by-step explanation: