Can any one help me at this q
1 answer:
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The inclusion/exclusion principle states that
That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).
Therefore,
will have the most elements when the sets 
and 
are disjoint, i.e. 
, which would mean the most we can can in this case would be
(Note that
denotes the cardinality of the set .)
That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).
Therefore,
(Note that
Hello!
If this long ribbon measures 144 feet, you can see, it was only multiplied by one number, which has the be the diameter of a column to get our circumference. If we divide this by our diameter 6 (diameter is double the radius, 3), we get our answer below.
144/6=24
Therefore, our answer is C) 24.
I hope this helps!