Answer:
I. 94.99 in²
II. $0.23
Step-by-step explanation:
<u>Given the following data;</u>
Diameter of wheel = 11 inches
Cost of wheel = $21.35

<em><u>Part A</u></em>
To find the area;
We know that a wheel is circular in nature. Thus, the area of a circle is given by the formula;
Substituting into the equation, we have;
<em>Area, A = 94.99 in²</em>
<em><u>Part B</u></em>
To find cost per square inch;
<u>Cost per square inch = $0.23</u>
Answer:
1.) m<6 and m<8=142, m<9=38
2.) m<7 and m<9=66, m<8=114
note: brainliest would be appreciated.
Step-by-step explanation:
Answer:
x ≈ 11.5
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Trigonometry</u>
- [Right Triangles Only] SOHCAHTOA
- [Right Triangles Only] sin∅ = opposite over hypotenuse
Step-by-step explanation:
<u>Step 1: Identify Variables</u>
Angle = 35°
Opposite Leg = <em>x</em>
Hypotenuse = 20
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [sine]: sin35° = x/20
- Isolate <em>x</em>: 20sin35° = x
- Evaluate: 11.4715 = x
- Rewrite: x = 11.4715
- Round: x ≈ 11.5
Answer:

Step-by-step explanation:
The volume of the solid revolution is expressed as;

Given y = 2x²
y² = (2x²)²
y² = 4x⁴
Substitute into the formula
![V = \int\limits^2_0 {4\pi x^4} \, dx\\V =4\pi \int\limits^2_0 { x^4} \, dx\\V = 4 \pi [\frac{x^5}{5} ]\\](https://tex.z-dn.net/?f=V%20%3D%20%5Cint%5Climits%5E2_0%20%7B4%5Cpi%20x%5E4%7D%20%5C%2C%20dx%5C%5CV%20%3D4%5Cpi%20%5Cint%5Climits%5E2_0%20%7B%20x%5E4%7D%20%5C%2C%20dx%5C%5CV%20%3D%204%20%5Cpi%20%5B%5Cfrac%7Bx%5E5%7D%7B5%7D%20%5D%5C%5C)
Substituting the limits
![V = 4 \pi ([\frac{2^5}{5}] - [\frac{0^5}{5}])\\V = 4 \pi ([\frac{32}{5}] - 0)\\V = 128 \pi/5 units^3](https://tex.z-dn.net/?f=V%20%3D%204%20%5Cpi%20%28%5B%5Cfrac%7B2%5E5%7D%7B5%7D%5D%20-%20%5B%5Cfrac%7B0%5E5%7D%7B5%7D%5D%29%5C%5CV%20%3D%204%20%5Cpi%20%28%5B%5Cfrac%7B32%7D%7B5%7D%5D%20-%200%29%5C%5CV%20%3D%20128%20%5Cpi%2F5%20units%5E3)
Hence the volume of the solid is 