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3 years ago

Write the equation of the line perpendicular to 2x-5y=-12 that passes through the point (10,-1)

Mathematics

1 answer:

sineoko [7]3 years ago

5 0

Answer:

y = - 5/2x + 24

Step-by-step explanation:

2x - 5y = - 12. (10, -1)

- 5y = - 2x - 12

y = -2/-5x -12/-5

y = 2/5x + 12/5

Slope: 2/5 (slope of the perpendicular line: - 5/2)

y - - 1) = - 5/2(x - 10)

y + 1 = - 5/2x + 25

y = - 5/2x + 24

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Lana71 [14]

Answer:

44 +14i

Step-by-step explanation:

(5 + i)(9 + i)

FOIL

first 5*9 = 45

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outer :5i

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45 + 9i+5i -1

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3 years ago

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Anni [7]

Answer:

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Step-by-step explanation:

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4 years ago

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FromTheMoon [43]

The answer is c.)1:32pm

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3 years ago

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When an object is thrown upwards with a speed of 64 ft/sec, its height above the ground is given by the function h(t)=−16t2+64t

Svet_ta [14]

Answer:

The object will reach its highest point 0.5 seconds after it has been thrown.

Step-by-step explanation:

The object reaches its maximum height when velocity is equal to zero, the velocity is the derivative of function height. That is:

$v(t) = \frac{d}{dt}h(t)$ (1)

Where $v(t)$ is the velocity of the object at time $t$ , in feet per seconds.

If we know that $h(t) =-16\cdot t^{2}+64\cdot t$ and $v(t) = 0\,\frac{ft}{s}$ , then the time when object reaches its highest point is:

$v(t) = -32\cdot t+64$

$-32\cdot t + 64 = 0$

$t = 0.5\,s$

The object will reach its highest point 0.5 seconds after it has been thrown.

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3 years ago

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netineya [11]

Symmetric property is the correct term

4 0

4 years ago