Given that,
The equation of line is y=7/5x+ 6 and that passes through the point (2,-6).
To find,
The equation of line that is perpendicular to the given line.
Solution,
The given line is :
y=7/5x+ 6
The slope of this line = 7/5
For two perpendicular lines, the product of slopes of two lines is :
Equation will be :
y=-5x/7+ b
Now finding the value of b. As it passes through (2,-6). The equation of line will be :
So, the required equation of line is :
y=-5x/7+ (-32/7)