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3 years ago

9

What best describes the expression y over 4? Some number divided by 4 Some number times 4 4 more than some number 4 less than so

me number

2 answers:

ss7ja [257]3 years ago

7 0

Answer:

Some number divided by 4

Step-by-step explanation:

Serhud [2]3 years ago

5 0

<em>y over 4 </em><em>means the number (y)</em><u><em /></u><em> </em><em>divided by 4.</em><u><em>
</em></u>

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What are the solution(s) of x2-4-0?

Elanso [62]

Answer:

For $x^2 - 4 = 0$ , x = 2, or x = - 2.

Step-by-step explanation:

Here, the given expression is :

$x^2 - 4 = 0$

Now, using the ALGEBRAIC IDENTITY:

$a^2 - b^2 = (a-b)(a+b)$

Comparing this with the above expression, we get

$x^2 - 4 = 0 = x^2 - (2)^2 = 0\\\implies (x-2)(x+2) = 0$

⇒Either (x-2) = 0 , or ( x + 2) = 0

So, if ( x- 2) = 0 ⇒ x = 2

and if ( x + 2) = 0 ⇒ x = -2

Hence, for $x^2 - 4 = 0$ , x = 2, or x = - 2.

4 0

3 years ago

Read 2 more answers

The pizza shop owner tells Mr. Lopez that 3 jumbo cookies can feed 10 students.

givi [52]

Answer:

j(x) = [ (3/10) cookie/student ]x

Step-by-step explanation:

The "unit rate" here is

3 jumbo cookies

------------------------- = (3/10) cookie/student

10 students

Then the number of cookies needed to feed x students is

j(x) = [ (3/10) cookie/student ]x

5 0

3 years ago

Question 2 (5 points)

IrinaK [193]

Answer:

$x - y + 5 = 0$

Step-by-step explanation:

Given:

Line passes through (-2,3) and (2,7)

Required:

Find the equation of the line

The equation of the line passing through two points is given by

$\frac{y-y_{1} }{y_{2}- y_{1} } =\frac{x_{}- x_{1} }{x_{2} -x_{1} }$

So, $\frac{y-3}{7-3} =\frac{x-(-2))}{2-(-2)}$

$\frac{y-3}{4} =\frac{x+2}{2+2}$

$\frac{y-3}{4} =\frac{x+2}{4}$

Now, $y-3 = x+2$

On rearranging,

$x - y + 3 + 2 = 0x - y + 5 = 0$

Therefore, the equation of the line is $x - y + 5 = 0.$

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2 years ago

Which inverse trigonometric function has a range of (0,pi)

Tems11 [23]

Answer:

cos − 1 ( x ) [ − 1 , 1 ] [ 0 , π ]

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3 years ago

Which of the following statements is true for a point in the first quadrant of the coordinate plane?

Ulleksa [173]

Answer:

Choice B: Start at the origin. Move $x$ units to the right, and $y$ units upwards.

Step-by-step explanation:

There are two axes on a typical Cartesian coordinate plane:

The horizontal $x$ -axis, and
The vertical $y$ -axis.

Many diagrams of a Cartesian plane would have arrows on these two axis. Typically, there would be:

a rightward arrow $\verb!->!$ on the right-hand side of the horizontal $x$ -axis, and
an upward arrow $\uparrow$ at top of the vertical $y$ -axis.

The arrow on the $x$ -axis pointing rightward suggests that as a point move to the right, the $x\!$ coordinate of that point would increase. Conversely, it would be necessary to move points to the right so as to increase their $\! x$ -coordinates.

On the other hand, the arrow pointing upwards on the $y$ -axis indicate that as a point move upward, the $y\!$ coordinate of that point would increase. With a similar logic, it would be necessary to move points upward to increase their $\! y$ -coordinates.

Besides, the origin (the intersection of the two axis, unless otherwise specified) would corresponds to $(0,\, 0)$ . (That is: $x = 0$ and $y = 0$ .) If the origin $(0,\, 0)\!$ is the starting point, it would be necessary to increase the $x$ -coordinate by $x\!$ units (by moving rightward $x\!\!$ units) and increase the the $y$ -coordinate by $y\!$ units (by moving upwards $y\!\!$ units) so as to reach the point $(x,\, y)$ .

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3 years ago