This is an example of conditional probability because we are trying to find the probability of an event occurring GIVEN the occurrence of some other event. There is a formula for this (see image attached).
If we follow this formula, the numerator would be the probability of (A AND B) which in this case is "48% of the class passed BOTH exams." The denominator in the formula would be that "60% of the class passed ONLY THE SECOND exam."
Therefore, P(A and B) = 0.48, which is 48% expressed as a decimal and P(B)= 0.60, which is 60% expressed as a decimal. Then, you can figure out the answer by dividing.
Answer:
#20 is irrational, #24 is 33/100, and #25 is 0
Step-by-step explanation:
Answer:
the answer is true
Step-by-step explanation:
the more you go negative the less it is so that's why -1 is greater than -8
80,000going up by 10% you just add the 10% on