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3 years ago

Work in the five days?

Mathematics

1 answer:

Ghella [55]3 years ago

7 0

Answer:

9.3

Step-by-step explanation:

last week she worked 45.6 hours. since 40 hours is the limit for normal working hours, she worked 45.6-40 = 5.6 hours overtime.

this week she worked 9.7+8.3+8+9.1+8.6 hours = 43.7 hours.

she worked therefore 43.7-40 = 3.7 hours overtime.

so, in total of the two weeks, she worked 5.6+3.7 = 9.3 hours overtime.

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Number 6 part a & b Number 7 Please & thank you

miv72 [106K]

Answer:

6- Part A: $750a+1200r=1000000$

Part B: $1065a+876r=1000000$

Solution of the system: $a\approx521.739\;\;\;\;b\approx507.246$

Step-by-step explanation:

Part A:

In words, the equation is formed like this:

Total kg of Arabica + Total kg of Robusta = Total kg of coffee

Now, the total of each yield is calculated by the product of kg/hectare and number of hectares. Thus, the equation is:

$750a+1200r=1000000$

Part B:

In words:

Arabica's worth + Robusta's worth = plantation worth

Each yield's worth is given by the product of the price per kg and the corresponding production. So, the equation is:

$1.42(750a)+0.73(1200r)=1000000\\1065a+876r=1000000$

3 0

3 years ago

How do you do #1 & #2 ?

Alexeev081 [22]

$Answer: \\ 1. \: x = \frac{ {32}^{2} }{24} = \frac{128}{3} \\y = \sqrt{ {24}^{2} + {32}^{2} } = 40\\ z = \frac{32 \times 40}{24} = \frac{160}{3} \\ \\ 2. \: x = \sqrt{( {4 \sqrt{5} )}^{2} - {8}^{2} } = 4$

7 0

3 years ago

Write the frost ten terms of a sequence whose first term is -10 and whose common difference is -2

Temka [501]

Answer:

$-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...$

Step-by-step explanation:

we know that

In an Arithmetic Sequence the difference between one term and the next is a constant, called the common difference

The formula for an Arithmetic Sequence is equal to

$a_n=a_1+(n-1)d$

where

d is the common difference

n is the number of terms

a_1 is the first term of the sequence

In this problem we have

$a_1=-10\\d=-2$

substitute

$a_n=-10+(n-1)(-2)$

$a_n=-10-2n+2$

$a_n=-2n-8$

Find the first ten terms

$a_1=-10$

For n=2 ----> $a_2=-2(2)-8=-12$

For n=3 ----> $a_3=-2(3)-8=-14$

For n=4 ----> $a_4=-2(4)-8=-16$

For n=5 ----> $a_5=-2(5)-8=-18$

For n=6 ----> $a_6=-2(6)-8=-20$

For n=7 ----> $a_7=-2(7)-8=-22$

For n=8 ----> $a_8=-2(8)-8=-24$

For n=9 ----> $a_9=-2(9)-8=-26$

For n=10 ----> $a_1_0=-2(10)-8=-28$

The sequence is

$-10,-12,-14,-16,-18,-20,-22,-24,-26,-28,...$

5 0

3 years ago

Complete the comparison: 26 <

EastWind [94]

26< any number larger than 26 (whole numbers and fractions/decimals)

6 0

3 years ago

Subtract.

jeka94

(x+1)-(-2x-5)
=x+1+2x+5
=3x+6
=3(x+2)

7 0

3 years ago

Read 2 more answers