Unclear. Did you mean
<span>f(x)= [sqrt of x+3]
--------------------
(x+8)
or did you mean
3
</span><span>f(x)= [sqrt of x] + ----------
x+8
I will focus on the first possibility. The domain of sqrt(x+3) is [-3,infinity).
The domain of x+3
------- is "x is not equal to -8."
x+8
Then the overall domain would be simply [-3, infinity).
</span>
Answer:
<h3>
It can be concluded that this polynomial has a degree of 2, so the equation x²+x−12=0 has exactly two root</h3>
Step-by-step explanation:
Given the quadratic polynomial x²+x−12, the highest power in the quadratic polynomial gives its degree. The degree of this quadratic polynomial is therefore 2. <u>This means that the equation has exactly two solutions. </u>
Let us determine the nature of the roots by factorizing the quadratic polynomial and finding the roots.
x²+x−12 = 0
x²+4x-3x−12 = 0
= (x²+4x)-(3x−12) = 0
= x(x+4)-3(x+4) = 0
= (x-3)(x+4) = 0
x-3 = 0 and x+4 = 0
x = 3 and -4
This shows that the quadratic polynomial has <u>two real roots</u>
<u>It can be concluded that this polynomial has a degree of 2, so the equation x²+x−12=0 has exactly two roots</u>
The general equation of a hyperbola with a horizontal transverse axis is defined as:
x²/a² - y²/b² = 1
Solving for b², we use the formula: a² + b² = c²
b² = 12² - 9² = 63
Equation of our hyperbola will be:
x²/81 - y²/63 = 1
Answer:
B is correct
Step-by-step explanation:
Answer: 37
Explanation:
Order of operations says you do multiplication first, you get 4 • 10 = 40
Then do subtraction, so 40 - 3 = 37
Hope this helps!
