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Ghella [55]
3 years ago
7

Help with rate question plz. Check my answer I got d. Idk if it’s correct and show your work if my answer’s wrong or correct

Mathematics
2 answers:
Aneli [31]3 years ago
4 0
Shop A is the correct answer.
According to the table, one shirt will cost $8 (16÷2=8, 24÷3=8), so the constant rate will be 8, same as shop A.
Marianna [84]3 years ago
3 0
The answer is Shop A. Because difference is by 8.

Hope this helps.
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Can someone please solve this?<br> a-3 Times a+7
Colt1911 [192]
You have to combine like terms.
Answer: -2a+7 

8 0
3 years ago
Read 2 more answers
You buy four packages of shoelaces. You pay with a $10 bill and receive $3.24 in change. Determine the price of each package.
Mnenie [13.5K]
I think each package would be $1.69. first you subtract 3.24 from 10 to get what you payed then divide that by 4 to get 1.69
8 0
3 years ago
Please help top and bottom.
Helga [31]
1. Perimeter
22a + 2(6a + 8) -4 = p

[I got 22a from 12a + 10a]

2. If p = 250, what is a?

22a + 2(6a + 8) - 4 = 250
Distributive property
22a + 12a + 16 - 4 = 250
Add like terms
34a + 12 = 250
Subtract 12 by both sides
34a = 238
Divide 34 by both sides
a = 7
3 0
2 years ago
The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?
Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

A(-6, 2)) = (x_1, y_1)

B(2, 6) = (x_2, y_2)

AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}

AB = \sqrt{(8)^2 + (4)^2}

AB = \sqrt{64 + 16} = \sqrt{80}

AB = 8.9 (nearest tenth)

Distance between B(2, 6) and C(7, 1):

BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

B(2, 6) = (x_1, y_1)

C(7, 1) = (x_2, y_2)

BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}

BC = \sqrt{(5)^2 + (-5)^2}

BC = \sqrt{25 + 25} = \sqrt{50}

BC = 7.1 (nearest tenth)

Distance between C(7, 1) and D(3, -5):

CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

C(7, 1) = (x_1, y_1)

D(3, -5) = (x_2, y_2)

CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}

CD = \sqrt{(-4)^2 + (-6)^2}

CD = \sqrt{16 + 36} = \sqrt{52}

CD = 7.2 (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

D(3, -5) = (x_1, y_1)

A(-6, 2) = (x_2, y_2)

DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}

DA = \sqrt{(-9)^2 + (7)^2}

DA = \sqrt{81 + 49} = \sqrt{130}

DA = 11.4 (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0
3 years ago
Can you add 23 and 40 without regrouping
Blizzard [7]
Yes because 0 and 4 dont equal 10 and 20 and 40 dont equal 100. So no and 40 + 23 = 63.
7 0
3 years ago
Read 2 more answers
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