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2 years ago

Please help asap with this question I'm really finding it tricky

Mathematics

1 answer:

Rina8888 [55]2 years ago

7 0

Answer:

0.7

Step-by-step explanation:

this is the answer because the zero means less in this equation.

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keon ha some change in his pocket then a friend loaned him 0.25 now keon has 1.45 in his pocket which equation can be used to fi

Studentka2010 [4]

Answer:

$1.45-$0.25=x

x=$1.20

Step-by-step explanation:

3 0

2 years ago

Which expression is equivalent to 3y+4+y

Colt1911 [192]

The answer to this question is 4y+4

8 0

2 years ago

What is 5/7 as a decimal?

Blababa [14]

<span>0.71428571 is your answer.</span>

8 0

3 years ago

Read 2 more answers

Answer the question in the picture

nekit [7.7K]

Recall the angle sum identities:

$\sin(x+y)=\sin x\cos y+\cos x\sin y$

$\cos(x+y)=\cos x\cos y-\sin x\sin y$

Now,

$\tan(x+y)=\dfrac{\sin(x+y)}{\cos(x+y)}=\dfrac{\sin x\cos y+\cos x\sin y}{\cos x\cos y-\sin x\sin y}$

Divide through numerator and denominator by $\cos x\cos y$ to get

$\tan(x+y)=\dfrac{\tan x+\tan y}{1-\tan x\tan y}$

Next, we use the fact that $x,y$ lie in the first quadrant to determine that

$\sin x=\dfrac12\implies\cos x=\sqrt{1-\sin^2x}=\dfrac{\sqrt3}2$

$\cos y=\dfrac{\sqrt2}2\implies\sin x=\sqrt{1-\cos^2x}=\dfrac1{\sqrt2}$

So we then have

$\tan x=\dfrac{\sin x}{\cos x}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

$\tan y=\dfrac{\sin y}{\cos y}=\dfrac{\frac1{\sqrt2}}{\frac{\sqrt2}2}=1$

Finally,

$\tan(x+y)=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3\approx3.73$

4 0

2 years ago

2(12x-11)=-4(1-6x)<br><br> Please write out how you got the answer.

Alekssandra [29.7K]

Hello.

2 (12x-11) = -4 (1-6x)

24x-22 = -4 + 24x

0 = 18

Undefined would be your answer. Be sure to double check.

Hope that helps.

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Disclaimer: Always double check your answer with a reliable source, as mistakes can be made.

3 0

3 years ago