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3 years ago

10x -15x + 5= -45 + 20

Mathematics

1 answer:

denpristay [2]3 years ago

4 0

Answer:

x=6

Step-by-step explanation:

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Whats 0909090909090909090909090909+4

LiRa [457]

Answer:

0909090909090909090909090913

Step-by-step explanation:

brainliest plz

6 0

2 years ago

Please Help!

allochka39001 [22]

It would be 4/15 is greater.
4/15 = 26% wrong
3/10 = 30% wrong

5 0

3 years ago

Read 2 more answers

Can you help with number 10 please?

Shalnov [3]

Answer: 7 Per Plain wrapping paper, and 8 Per Shiny wrapping paper

Hope this helps :)

6 0

3 years ago

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A park has a large circle painted in the middle of the playground area.thecircle is divided into 4 equal sections And each secti

lilavasa [31]

Answer:

The area of each section of the circle is $25\pi\ m^{2}$

Step-by-step explanation:

we know that

The area of a circle is equal to

$A=\pi r^{2}$

we have

$r=10\ m$

substitute

$A=\pi (10^{2})=100\pi\ m^{2}$

To find the area of each section divide the complete area of the circle by $4$

$100\pi\ m^{2}/4=25\pi\ m^{2}$

8 0

3 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

2 years ago