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stiks02 [169]
3 years ago
14

OT bisects ∠DOG. Find the measure of ∠DOG if ∠DOT = 4x + 4 and ∠TOG = 5x – 3

Mathematics
1 answer:
g100num [7]3 years ago
6 0

Answer:

\huge\boxed{64^o}

Step-by-step explanation:

If OT is bisects ∠DOG, then m∠DOT = m∠TOG. Therefore

4x+4=5x-3    |<em>subtract 4 from both sides</em>

<em />4x+4-4=5x-3-4\\\\4x=5x-7<em>|subtract 5x from both sides</em>

<em />4x-5x=5x-5x-7\\\\-x=-7<em>|change the signs</em>

<em />x=7<em />

Calculate the measure of ∠DOG

m∠DOG = 2(m∠DOT)

m\angle DOG=2(4\cdot7+4)=2(28+4)=2(32)=64

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