OT bisects ∠DOG. Find the measure of ∠DOG if ∠DOT = 4x + 4 and ∠TOG = 5x – 3

Mathematics

1 answer:

g100num [7]3 years ago

6 0

Answer:

$\huge\boxed{64^o}$

Step-by-step explanation:

If OT is bisects ∠DOG, then m∠DOT = m∠TOG. Therefore

$4x+4=5x-3$ |subtract 4 from both sides

$4x+4-4=5x-3-4\\\\4x=5x-7$ |subtract 5x from both sides

$4x-5x=5x-5x-7\\\\-x=-7$ |change the signs

$x=7$

Calculate the measure of ∠DOG

m∠DOG = 2(m∠DOT)

$m\angle DOG=2(4\cdot7+4)=2(28+4)=2(32)=64$

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