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2 years ago

10

Prem has $45000 to invest for 1 year. The bank tells him the interest rate is 6%. Calculate how much the investment is worth at

the end of the year…
1) If the interest is paid every 6 months
2) If interest is paid quarterly

1 answer:

il63 [147K]2 years ago

5 0

Answer:

1) $47,740.50

2) $47,761.36

Step-by-step explanation:

hope this helps :)

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8 (Picture) CONVERGENT AND DIVERGENT SERIES PLEASE HELP!!

djverab [1.8K]

Answer:

<em>The correct answer choice is: B</em>

Step-by-step explanation:

<u>Culture A</u>

Initial number of cells = 1000

The number of cells is raised by 200 each day and every day thereafter.

So, the number of cells raised in one month(30 days) $=200\times 30=6000$

Thus, the total number of cells in culture A at the end of one month will be: $1000+6000=7000$

<u>Culture B</u>

Initial number of cells = 1000

The number of cells is increased by 8% each day and every day thereafter.

<em>Formula for exponential growth is:</em> $A=P(1+r)^t$ , where $P=$ Initial amount, $A=$ Final amount, $r=$ Rate of growth in decimal form and $t=$ Time duration.

Using the above formula, the number of cells after 30 days will be.....

$A= 1000(1+0.08)^3^0\\ \\ A=1000(1.08)^3^0= 10062.656...$

That means, Culture B is more effective in promoting cell growth.

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3 years ago

Sebastian's pool is filled with 270 cubic meters of water. The base of the pool is 15 m long and 9 m wide. What is the height of

vodomira [7]

I got 2 m as the answer.

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3 years ago

Is 9.9 x 10/-28 in scientific notation

Katen [24]

Yes and no you do not use the slash you use ^

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3 years ago

The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

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3 years ago

Solve the problem by writing an inequality. A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 per T

pashok25 [27]

<h3>Hello there i hope you are having good day :) Question : Solve the problem by writing an inequality. = A club decides to sell T-shirts for $12 as a fund-raiser. It costs $20 plus $8 per T-shirt to make the T-shirts. Write and solve an equation to find how many T-shirts the club needs to make and sell in order to profit at least $100. Show your work? = So firstly the each of the shirt cost $12 and the money made for the shirt equals 12$ so the cost per the shirt would be 20 + 8x that lead to needing at least 100$ amount made - cost = profit would equal to 12x - (20-8x) ≥ 100 then you would do 12x-20-8x = 100 then you would also do 4x-20 = 100 then you add 20 and add 20 again that would equal 4x/4x = 120/4 that would finally lead you to the answer that would be x = 30 ---> x ≥ 30</h3><h3>Hopefully this help you.</h3>

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3 years ago