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2 years ago

10

Prem has $45000 to invest for 1 year. The bank tells him the interest rate is 6%. Calculate how much the investment is worth at

the end of the year…
1) If the interest is paid every 6 months
2) If interest is paid quarterly

1 answer:

il63 [147K]2 years ago

5 0

Answer:

1) $47,740.50

2) $47,761.36

Step-by-step explanation:

hope this helps :)

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A random sample of n = 45 observations from a quantitative population produced a mean x = 2.5 and a standard deviation s = 0.26.

oee [108]

Answer:

P-value (t=2.58) = 0.0066.

Note: as we are using the sample standard deviation, a t-statistic is appropiate instead os a z-statistic.

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the population mean μ exceeds 2.4.

Then, the null and alternative hypothesis are:

$H_0: \mu=2.4\\\\H_a:\mu> 2.4$

The significance level is 0.05.

The sample has a size n=45.

The sample mean is M=2.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.26.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.26}{\sqrt{45}}=0.0388$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{2.5-2.4}{0.0388}=\dfrac{0.1}{0.0388}=2.58$

The degrees of freedom for this sample size are:

$df=n-1=45-1=44$

This test is a right-tailed test, with 44 degrees of freedom and t=2.58, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t>2.5801)=0.0066$

As the P-value (0.0066) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the population mean μ exceeds 2.4.

7 0

3 years ago

-8=-16+m <br> pls show work! ty

rosijanka [135]

Answer:

-8=-16+m

-8+16=m

m=8

I would appreciate if my answer is chosen as a brainliest answer

6 0

2 years ago

Read 2 more answers

HELP, I AM UTTERLY CONFUSED *20 points

Studentka2010 [4]

Ok so this question is a bit complicated, but it's easier to understand if you break it down into smaller parts!

1) First, you know that ABGF is half the perimeter of ACDE. This means that the length of one side of ABGF must be 1/2 the length of one side of ACDE.
>> You can think of this by putting in random numbers. Say the perimeter of the larger square is 24 and the perimeter of the smaller square is 12. That means one side of the larger square of 24/4 (b/c four sides) = 6 and one side of the smaller square is 12/4 = 3!

2. Ok know you know the lengths of the sides relative to each other, but you're only given one value: 4in. Since the smaller square has sides that are 1/2 the larger squares, you know that it makes up 1/4 of the larger square! So imagine 4 of those smaller squares filling up that larger square to make a 2 by 2. It just so happens that 4in is the diagonal going through one of our imaginary squares, which is equal in size to ABGF!

3. Now use the 45-45-90 rule to figure out the length of one side of that imaginary square because the 4in diagonal splits that imaginary square into two of those 45-45-90 triangles. You know the hypotenuse of that triangle is 4in. That means one of the legs is 4/✓2 (since the rule says that the hypotenuse and the leg are in a ✓2:1 ratio). And like we said before the length of that leg is the length of the side of our imaginary square. And our imaginary square must be the same size as ABGF! So now we know the side of the smaller square to be 4/✓2!

4. Multiply the side of the smaller square by 2 to get the side of our larger square. (4/✓2)*2=8/✓2

5. Now to find the area of the shaded region, just find the area of the smaller square ABGF and subtract from the larger square ACDE. Use equation for the area of a square!
$a = {s}^{2}$
where s=the length of one side.

The length of one side of the smaller square is 4/✓2. So it's area is:
${( \frac{4}{ \sqrt{2} }) }^{2} = \frac{16}{2} = 8$

The length of one side of the larger square is 8/✓2. So it's area is:
${ ( \frac{8}{ \sqrt{2} }) }^{2} = \frac{64}{2} = 32$

Now subtract. 32-8=24! :)

Hope this helps! Let me know if you have any questions.

3 0

3 years ago

What is the value of tan C in this triangle?

goblinko [34]

Answer:

$\large\boxed{\dfrac{24}{7}}$

Step-by-step explanation:

$tangent=\dfrac{opposite}{adjacent}$

We have

$opposite=24\\adjacent=7$

Substitute:

$\tan C=\dfrac{24}{7}$

5 0

3 years ago

In triangle ABC show find BC..<br><br><br> Need help ASAP!!!

Temka [501]

Answer: BC=22cm

Step-by-step explanation:

5d-3=3d+7

2d=10

d=5

plug 5 into the equation for BC, and you get 22

3 0

2 years ago

Read 2 more answers