Please help!!!!!!!!!!

Mathematics

1 answer:

Sunny_sXe [5.5K]2 years ago

7 0

Answer:

From the chapter Playing with numbers

we can define derek has 2×10^2 + 7 × 10^1 + 7× +0^0

as If ABC a number then ABC can be written as 10^2A+10^1B+10^0C

Hope it helps

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Arturiano [62]

Answer: d

Step-by-step explanation:

7 0

3 years ago

Callan is buying a square shaped platter with an area of 169 square inches what is the correct step he should take if he wants t

bagirrra123 [75]

a = length of one side.

Area of a square = a^2

in our problem,

Area = 169 square inches

a = ?

Plug our numbers into the area formula mentioned above.

169 in^2 = a^2.

Take the square root of each side to find the side length of the square shaped platter.

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2 years ago

A half-century ago, the mean height of women in a particular country in their 20s was 64.7 inches. Assume that the heights of

Ainat [17]

Answer:

99.5% of all samples of 21 of today's women in their 20's have mean heights of at least 65.86 inches.

Step-by-step explanation:

We are given that a half-century ago, the mean height of women in a particular country in their 20's was 64.7 inches. Assume that the heights of today's women in their 20's are approximately normally distributed with a standard deviation of 2.07 inches.

Also, a samples of 21 of today's women in their 20's have been taken.

Let $\bar X$ = sample mean heights

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean height of women = 64.7 inches

$\sigma$ = standard deviation = 2.07 inches

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample of 21 of today's women in their 20's have mean heights of at least 65.86 inches is given by = P( $\bar X$ $\geq$ 65.86 inches)

P( $\bar X$ $\geq$ 65.86 inches) = P( $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ $\geq$ $\frac{65.86-64.7}{\frac{2.07}{\sqrt{21} } }$ ) = P(Z $\geq$ -2.57) = P(Z $\leq$ 2.57)