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seropon [69]
3 years ago
9

For the following set of data, find the number of data within 1 population standard deviation of the mean. Data Frequency 15 1 1

6 7 17 11 21 13 22 12 25 9 28 6 30 1
i need this quckly please
​
Mathematics
1 answer:
RUDIKE [14]3 years ago
6 0
The mean age of the frequency distribution for the ages of the residents of a town is 43 years.
Step-by-step explanation:
We are given with the following frequency distribution below;
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WILL GIVE BRINALIEST!
Liono4ka [1.6K]

-21,  -23, -27, -28, -28, -29 order them least to greatest and then find the middle if there is not a middle then put -27.5 as your answer for the median. For the mean add up all the number then you should get -156 then divide it by 6 which should give you -26 for the mean.  and for the mode you should get -28 as the one that occurs the most often.

mean: -26

median: -27.5

mode: -28

4 0
3 years ago
Caroline and Helen share a job in the ratio 3:2.
Simora [160]

Answer:

helen works 16 hours

Step-by-step explanation:

caroline = 3 which is 24 hours

24/3 = 8

1 = 8 hours

8 hours x 2 = 16 hours

7 0
3 years ago
Trying to help my bro solve this <br>Y= -2x+2
Alexus [3.1K]
Are you trying to graph it because it is in y=mx+b form.

3 0
4 years ago
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Divide.<br><br> 6,029 ÷ 28<br><br> Enter your answer by filling in the boxes.<br><br> __R__
GenaCL600 [577]
215 R.32 that is the answer
6 0
3 years ago
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Jack usually mows his lawn in 6 hours. marilyn can mow the same yard in 4 hours. How much time would it take for them to mow the
Anuta_ua [19.1K]

Answer:

2.4 hours or 2 hours and 24 minutes

Step-by-step explanation:

Jack mows 1/6 of the lawn per hour while Marilyn mows 1/4 of the lawn together. Adding up those rates yields in their combined mowing rate:

R = \frac{1}{6}+ \frac{1}{4}\\R=\frac{10}{24}

The time required for them to mow the entire lawn is:

t = \frac{1}{R}\\t = \frac{1*24}{10}\\ t=2.4\ hours

It would take them both 2.4 hours to mow the lawn together.

5 0
3 years ago
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