Answer:
D
Step-by-step explanation:
a substance made by mixing other substances together.
Answer:
34.6 units
Step-by-step explanation:
The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.
The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).
Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:
Distance between point A(-6, 2) and point B(2, 6):

Let,





(nearest tenth)
Distance between B(2, 6) and C(7, 1):

Let,





(nearest tenth)
Distance between C(7, 1) and D(3, -5):

Let,





(nearest tenth)
Distance between D(3, -5) and A(-6, 2):

Let,





(nearest tenth)
Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units
Answer:
x = 26.45
Step-by-step explanation:
Cos theta = adjacent side / hypotenuse
cos 50 = 17 /x
Switch the x and the cos 50
x = 17 / cos 50
x =26.44730506
Rounding to 2 decimal places
x = 26.45
Y = a (x + 3)² - 1
Let's take the point (-1;3)
3 = a ( -1 + 3)² - 1
3 = 4a - 1
4a = 4
Therefore a = 4/4 = 1
(x+3)² - 1
= x² + 6x + 9 - 1
= x² + 6x + 8
The answer would be y = x² + 6x + 8.
Hope this helps !
Photon
Answer:
The correct answer is (E).
This is not an experiment because no treatment is being imposed upon the customers. Additionally, this study used a stratified sample because independent random samples were selected from two distinct populations of customers.
Step-by-step explanation: