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Anit [1.1K]
3 years ago
6

The equation y = negative StartFraction 1 Over 20 EndFraction x + 10 represents the gallons of gasoline that remain in Michelle’

s car after she drives x miles. Which graph represents this equation?
A graph titled Driving has total miles traveled on the x-axis and gallons of gasoline on the y-axis. A line goes through points (0, 10) and (40, 8).

A graph titled Driving has total miles traveled on the x-axis and gallons of gasoline on the y-axis. A line goes through points (0, 11) and (80, 8).

A graph titled Driving has total miles traveled on the x-axis and gallons of gasoline on the y-axis. A line goes through points (0, 12) and (125, 6).

A graph titled Driving has total miles traveled on the x-axis and gallons of gasoline on the y-axis. A line goes through points (0, 10) and (150, 0).
Mathematics
1 answer:
denis23 [38]3 years ago
8 1

wait I think that you need to umm

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Answer:

Most known one: 4 sides

Step-by-step explanation:

They are closed shapes, their sides should be straight, they are strictly 2 dimensional, and finally, all quadrilaterals have 4 sides.

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Order of operation? 5p^2 = h when p =2 and h = 8
Naddika [18.5K]

Given: p=2, h=8

5p^2=h

5(2)^2=8 ------- substitution here

5(4)=8

20 doesn't equal 8

I did exponents first because it comes before multiplication in the order of opertions.

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7 0
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ALGEBRA 2 100 POINTS
dybincka [34]
  • f(3)=6
  • g(-2)=10
  • \sf f^{-1}(5)=-1
  • \sf g^{-1}(-10)=4

Table attached

4 0
3 years ago
Read 2 more answers
Statistics In the manual “How to Have a Number One the Easy Way,” it is stated that a song “must be no longer than three minutes
dimaraw [331]

Answer:

We conclude that the sample is from a population of songs with a mean greater than 210 seconds.

Step-by-step explanation:

We are given that a simple random sample of 40 current hit songs results in a mean length of 252.5 seconds.

Assume that the standard deviation of song lengths is 54.5 sec.

Let \mu = <u><em>population mean length of the songs</em></u>

So, Null Hypothesis, H_0 : \mu \leq 210 seconds      {means that the sample is from a population of songs with a mean smaller than or equal to 210 seconds}

Alternate Hypothesis, H_A : \mu > 210 seconds      {means that the sample is from a population of songs with a mean greater than 210 seconds}

The test statistics that will be used here is <u>One-sample z-test statistics </u>because we know about population standard deviation;

                              T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of songs = 252.5 seconds

            \sigma = population standard deviation = 54.5 seconds

            n = sample of current hit songs = 40

So, <u><em>the test statistics</em></u> =  \frac{252.5-210}{\frac{54.5}{\sqrt{40} } }

                                   =  4.932

The value of z-test statistics is 4.932.

Now, at 0.05 level of significance, the z table gives a critical value of 1.645 for the right-tailed test.

Since the value of our test statistics is more than the critical value of z as 4.932 > 1.645, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the sample is from a population of songs with a mean greater than 210 seconds.

4 0
3 years ago
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