Answer:
- The value of

- The value of

Step-by-step explanation:
Let

and

As
is exactly divisible, so, the remainder is 0.
∴ 

As the R.H.S becomes 0 when
and
.
And
by substituting 

![25 + 20( \frac{\sqrt{5}}{\sqrt{2}} ) + a( \frac{\sqrt{5}}{\sqrt{2}}) +b =0...[A]](https://tex.z-dn.net/?f=25%20%2B%2020%28%20%5Cfrac%7B%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B2%7D%7D%20%29%20%2B%20a%28%20%5Cfrac%7B%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B2%7D%7D%29%20%2Bb%20%3D0...%5BA%5D)
by substituting 
![25 - 20( \frac{\sqrt{5}}{\sqrt{2}} ) - a( \frac{\sqrt{5}}{\sqrt{2}}) +b =0.....[B]](https://tex.z-dn.net/?f=25%20-%2020%28%20%5Cfrac%7B%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B2%7D%7D%20%29%20-%20a%28%20%5Cfrac%7B%5Csqrt%7B5%7D%7D%7B%5Csqrt%7B2%7D%7D%29%20%2Bb%20%3D0.....%5BB%5D)
Adding Equation [A] and equation [B]


Subtracting Equation [A] and equation [B]


Therefore,
- The value of

- The value of

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Step-by-step explanation:
i hope this helps you :)