From the information in the problem, the ratio of defective cameras to cameras shipped is
. Reducing this ratio, we get the simplified form of
which, incidentally, gives us our answer. We have
1 defective camera for every 200 cameras shipped.
Answer:
Truck can safely carry <em>2310 pounds </em> of cargo.
Step-by-step explanation:
Given the safety limit of weight to cross the bridge safely is 4 tons.
1 ton is equal to 2000 pounds.
so, 4 tons are equal to 2000 
4 = 8000 pounds
Now, given that
weight of empty truck and driver = 5690 pounds
To find:
Weight of cargo that the truck can safely carry ?
Solution:
Total weight of the truck is actually the combined weight of the empty truck, the drive and the cargo carried in it.
So, Total Weight allowed = 8000 pounds = 5690 pounds + Weight of Cargo
Weight of Cargo = 8000 - 5690 pounds
Weight of Cargo = <em>2310 pounds</em>
Truck can safely carry <em>2310 pounds </em> of cargo.
The vertex form is y=7(x+1)^2-3
A^2 + b^2 = c^2
C is your hypotenuse or the longest side of the triangle; you plug in your values and solve for the missing side:
15^2 + b^2 = 17^2
225 + b^2 = 289
*-225 on both sides to get b by itself*
B^2 = 64
*to get rid of the ^2; you take the square root*
B = sqrt 64
B= 8 <— final answer
Answer:
Can't see the answer choices
the figure it translated across the Y-Axis
