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3 years ago

The element in group 5 and period 5

Chemistry

2 answers:

horrorfan [7]3 years ago

7 0

Look on the periodic table lol

OverLord2011 [107]3 years ago

3 0

Answer:

Silver(Ag)

Explanation:

there are multiple but this one that I know for a fact in that category

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If a polypeptide synthesized by a ribosome contains 99 amino acids in the chain, how many codons (including the start and stop c

Rudiy27

Explanation:

<u>-101 mRNA codons</u>

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In the genetic code, an amino acid is encoded by 3 nucleotides, while there are just 4 bases . Each amino acid is specifically encoded by a codon- a triplet sequence of nucleotides...

Thus 99 amino acids= 99 codon sequences.

...along with a start and stop codon, this would require 101 mRNA codons

Further Explanation:

The nucleic acids are comprised of smaller units called nucleotides and function as storage for the body’s genetic information. These monomers include ribonucleic acid (RNA) or deoxyribonucleic acid (DNA). They differ from other macromolecules since they don’t provide the body with energy. They exist solely to encode and protein synthesis.

Basic makeup: C, H, O, P; they contain phosphate group 5 carbon sugar does nitrogen bases which may contain single to double bond ring.

Codons are three nucleotide bases encoding an amino acid or signal at the beginning or end of protein synthesis.

RNA codons determine certain amino acids so the order in which the bases occur within in the codon sequence designates which amino acid is to be made bus with the four RNA nucleotides (Adenine, Cysteine and Uracil) Up to 64 codons (with 3 as stop codons) determine amino acid synthesis. The stop codons ( UAG UGA UAA) terminate amino acid/ protein synthesis while the start codon AUG begins protein synthesis.

Learn more about transcription at brainly.com/question/11339456

Learn more about DNA and RNA brainly.com/question/2416343?source=aid8411316

#LearnWithBrainly

5 0

3 years ago

What is the molarity if 60.4 grams of hydrochloric acid was added to 505 mL of water?

ANTONII [103]

Answer:

3.29 M

Explanation:

Molarity refers to the molar concentration of a solution and it can be calculated using the formula below:

Molarity (M) = number of moles (n) ÷ volume (V)

According to this question, the mass of HCl was given to be 60.4 grams and the volume of water as 505 mL.

Using mole = mass/molar mass to convert mass of HCl to moles

Molar mass of HCl = 1.0079 + 35.453 = 36.4609g/mol

mole = 60.4g ÷ 36.4609g/mol

mole = 1.66mol

Volume of water = 505mL = 505/1000 = 0.505L

Molarity, M = 1.66 ÷ 0.505

Molarity of HCl solution = 3.29 M

8 0

3 years ago

How many grams of NaC2H3O2 are needed to prepare 350. mL of a 2.75 M solution? (molar mass of

shepuryov [24]

Answer:

78.96 g of NaC2H3O2

Explanation:

We are given;

Volume of the solution as 350 mL
Molarity of the solution as 2.75 M
Molar mass of the solute NaC2H3O2 as 82.04 g/mol

We are required to determine the mass of the solute;

First we determine the number of moles;

Moles = Molarity × Volume

Therefore;

Moles of the solute = 2.75 M × 0.350 L

= 0.9625 moles

Second, we determine the mass

Mass = Moles × Molar mass

= 0.9625 moles × 82.04 g/mol

= 78.9635 g

= 78.96 g

Therefore, the mass of NaC2H3O2 needed is 78.96 g

4 0

3 years ago

Match the following aqueous solutions with the appropriate letter from the column on the right. Assume complete dissociation of

Serhud [2]

Answer: 0.17 m $CH_3COONH_4$ : Highest freezing point

0.20 m $CoSO_4$ : Second lowest freezing point

0.18 m $MnSO_4$ : Third lowest freezing point

0.42 m ethylene glycol: Lowest freezing point

Explanation:

Depression in freezing point is a colligative property which depend upon the amount of the solute.

$\Delta T_f=i\times k_f\times m$

where,

$\Delta T_f$ = change in freezing point

i= vant hoff factor

$k_f$ = freezing point constant

m = molality

a) 0.17 m $CH_3COONH_4$

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i =2 for $CH_3COONH_4$ , thus total concentration will be 0.34 m

b) 0.18 m $MnSO_4$

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for $MnSO_4$ , thus total concentration will be 0.36 m

c) 0.20 m $CoSO_4$

For electrolytes undergoing complete dissociation, vant hoff factor is equal to the number of ions it produce. Thus i = 2 for $CoSO_4$ , thus total concentration will be 0.40 m

d) 0.42 m ethylene glycol

For non electrolytes undergoing no dissociation, vant hoff factor is equal to 1 . Thus i = 1 for ethylene glycol, thus concentration will be 0.42 m

The more is the concentration, the highest will be depression in freezing point and thus lowest will be freezing point.

4 0

3 years ago

Describe the process of condensation.

Alexxx [7]

there is a system like evaporation the water water evaporates to give condensation is were all the water forms into a cloud and when it gets a lot of water you get persipition is when it rains

8 0

4 years ago