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zavuch27 [327]
3 years ago
6

Question 6 of 10

Mathematics
1 answer:
Yuliya22 [10]3 years ago
6 0

Answer:

x=9

Step-by-step explanation:

x-1=8 (add 1 from both sides)

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Answer:

D

Step-by-step explanation:

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3 years ago
A 30° 60° 90° triangle is shown below. Find the length of the side labeled y.
bulgar [2K]

Answer:

Part 1) y=3\ units

Part 2) The length of the hypotenuse is 6 units

Step-by-step explanation:

Part 1) we know that

In the right triangle of the figure

sin(60^o)=\frac{y}{2\sqrt{3}} ----> by SOH (opposite side divided by the hypotenuse)

solve for y

y=sin(60^o)2\sqrt{3}

Remember that

sin(60^o)=\frac{\sqrt{3}}{2}

substitute

y=(\frac{\sqrt{3}}{2})2\sqrt{3}

y=3\ units

Part 2)

Let

h ----> the length of the hypotenuse

we know that

In the right triangle of the figure

sin(45^o)=\frac{3\sqrt{2}}{h} ----> by SOH (opposite side divided by the hypotenuse)

h=\frac{3\sqrt{2}}{sin(45^o)}

Remember that

sin(45^o)=\frac{\sqrt{2}}{2}

substitute

h=3\sqrt{2}:\frac{\sqrt{2}}{2}

h=6\ units

7 0
3 years ago
Select all the correct locations on the table. Select all of the complex numbers in the given table.
goblinko [34]

Answer:

answer in  picture

Step-by-step explanation:

4 0
4 years ago
Let tk(x)tk(x): be the taylor polynomial of degree k of the function f(x)=sin(x)f(x)=sin⁡(x) at a=0a=0.suppose you approximate f
Aloiza [94]
<span>Ans : Note that: sin(x) = sum(n=0 to infinity) [(-1)^n * x^(2n + 1)]/(2n + 1)!. Then, since the series is alternating, the error in the approximation found by taking the first n terms of the series is no bigger than the n+1'th term. In other words: E ≤ a_n+1 = x^(2n + 3)/(2n + 3)!. (Note that a_n does not include (-1)^n, the alternating part) We need that 1/6 ≤ x^(2n + 3)/(2n + 3)!. Given |x| < 1, n = 2 will be the least integer solution. Thus, we need 2 + 1 = 3 terms.</span>
4 0
3 years ago
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