Answer with explanation:

Average Height of tallest Building in San Francisco

Average Height of tallest Building in Los Angeles

→→Difference between Height of tallest Building in Los Angeles and Height of tallest Building in San Francisco
=233.9-197.8
=36.1
⇒The average height of the 10 tallest buildings in Los Angeles is 36.1 more than the average height of the tallest buildings in San Francisco.
⇒Part B
Mean absolute deviation for the 10 tallest buildings in San Francisco
|260-197.8|=62.2
|237-197.8|=39.2
|212-197.8|=14.2
|197 -197.8|= 0.8
|184 -197.8|=13.8
|183-197.8|=14.8
|183-197.8|= 14.8
|175-197.8|=22.8
|174-197.8|=23.8
|173 -197.8|=24.8
Average of these numbers

Mean absolute deviation=23.12
If You know how to do long division then... You move the decimal that’s outside the house to where it’s not there no more then divide . Or turn the decimals into Fractions and do the reciprocal.
C. Claire could be 6 foot 8 while Alice could be 5 feet.
D. It would be 3/4 to 4/4 because Alice is 1/4 shorter than Claire.
3/4 : 4/4 | 6/8 : 8/8 | 9/12 : 12/12 | etcetera.
It will be 3 weeks because if you divide 7/2,100 it will become to be 3weeks