Y’’(x)= 6x + 1
y’(x)= 3x^2 + x + 2
y(x)= x^3 + 1/2x^2 + 2x + 5
The domain and range of the given function are equal to (0, 3.85) and (0, 18.75) respectively.
<h3>How to calculate the domain of the function?</h3>
In this exercise, you're given the following function h(t) = -4.87t² + 18.75t. Next, we would equate the function to zero (0) to determine its domain as follows:
0= -4.87t² + 18.75t.
4.87t(-t + 3.85) = 0
t = 0 or t = 3.85.
Therefore, the domain is 0 ≤ t ≤ 3.85 or (0, 3.85).
<h3>How to calculate the range of the function?</h3>
h(t) = -4.87t² + 18.75t
h(t) = -4.87(t² - 3.85t + 3.85 - 3.85)
h(t) = -4.87(t - 1.925)² + 18.05
Therefore, the range is 0 ≤ h ≤ 18.05 or (0, 18.75).
Read more on domain here: brainly.com/question/17003159
#SPJ1
Answer:
6
Step-by-step explanation:
Answer: i believe it would be (-3 , 5)
Step-by-step explanation:
Correct me if im wrong
Answer:
m<5 = 95 degrees
Step-by-step explanation:
Let's first find m<1
=> m<1 = 180-85
=> m<1 = 95 degrees
Since,
m<1 = m<5 (Corresponding angles)
So,
m<5 = 95 degrees
