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2 years ago

1. Given f(x) =1/4 (x – 8), what is the value of f(24)?

Mathematics

2 answers:

goldenfox [79]2 years ago

8 0

Hi there!

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I believe your answer is:

$f(24)=4$

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Here’s why:

⸻⸻⸻⸻

$f(x)=\frac{1}{4}(x-8)\\-----------\\\rightarrow f(24)= \frac{1}{4}(24-8)\\\\\rightarrow f(24) = \frac{1}{4}( 16)\\\\\rightarrow\boxed{f(24)=4}$

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Hope this helps you. I apologize if it’s incorrect.

Vitek1552 [10]2 years ago

3 0

The answer is 4 because if x=24, then 24-8 is 16, and 1/4 of 16 is 4

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A line with a slope of 1/8 passes through the points (u, -9) and (6, -8). what is the value of u?

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Answer:
u = -2

Explanation:
Slope of the line can be calculated using the following rule:
slope = (y2-y1) / (x2-x1)

We are given :
slope = 1/8
point (u,-9) represent (x1,y1)
point (6,-8) represent (x2,y2)

Substitute with the givens in the above equation and solve for u as follows:
slope = (y2-y1) / (x2-x1)
1/8 = (-8--9) / (6-u)
1/8 = (1) / (6-u)
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3 years ago

A photo booth in the shape of a rectangular prism has edge lengths of 3 ft by 4 ft by 7 ft. What is the volume of the space insi

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Step-by-step explanation:

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2 years ago

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I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

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1 year ago

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Step-by-step explanation:

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