Answer:
155
Step-by-step explanation:
The problem sounds complicated, but it's not. Let's analyse.
The city manager have come up with an equartion y=11x +12, with Y is the total number of the stores and X stands for how long it has been since 2003.
We can't explain how the manager came up with this equation, so iwe don't need to think of if the equation is real or not. Let's just base on what we have.
Because the equation aboce is a trendy line, it means that it would likely to be true with any X ( number of years since 1990).
In Tracy's case, the year is 2003, so it has been 2003 - 1990 = 13 years since 1990. This is the X in the equation. Now we only need to find Y in the equation, which is the number of retail stores there were in 2003, exactly what the problem asks.
y= 11x + 12
=> In Tracy's case: y= 11*13 + 12= 155
So the number of retail stores there were in 2003 was 155
Answer:
3 blue birds
Step-by-step explanation:
To answer this question, simply subtract:
8 - 5 = 3
So, Trevor saw 3 blue birds
Hope this helps!
Total distance covered by <span>George and Carmen
</span>x + y = 350
And they biked 80 kilometers more than they bussed
<span>80 + y = x </span>
Putting the value of x=80 + y in <span>x + y = 350:
</span>We get:
<span>80 + y + y = 350 </span>
<span>2y = 270 </span>
<span>y = 135 km</span>
<span>Substituting y = 135 in x + y = 350 </span>
<span>x + 135 = 350</span>
<span>x = 215 km </span>
Thus George and Carmen biked for 215 km and bussed for 135 km.
The answer is D.
|-4| < 4
4 < 4
|-1| < 0
1 < 0
|-6| = -6
6 = -6
|-14| > 10
14 > 10
Answer:
20. AB = 42
21. BC = 28
22. AC = 70
23. BC = 20.4
24. FH = 48
25. DE = 10, EF = 10, DF = 20
Step-by-step explanation:
✍️Given:
AB = 2x + 7
BC = 28
AC = 4x,
20. Assuming B is between A and C, thus:
AB + BC = AC (Segment Addition Postulate)
2x + 7 + 28 = 4x (substitution)
Collect like terms
2x + 35 = 4x
35 = 4x - 2x
35 = 2x
Divide both side by 2
17.5 = x
AB = 2x + 7
Plug in the value of x
AB = 2(17.5) + 7 = 42
21. BC = 28 (given)
22. AC = 4x
Plug in the value of x
AC = 4(17.5) = 70
✍️Given:
AC = 35 and AB = 14.6.
Assuming B is between A and C, thus:
23. AB + BC = AC (Segment Addition Postulate)
14.6 + BC = 35 (Substitution)
Subtract 14.6 from each side
BC = 35 - 14.6
BC = 20.4
24. FH = 7x + 6
FG = 4x
GH = 24
FG + GH = FH (Segment Addition Postulate)
(substitution)
Collect like terms


Divide both sides by -3

FH = 7x + 6
Plug in the value of x
FH = 7(6) + 6 = 48
25. DE = 5x, EF = 3x + 4
Given that E bisects DF, therefore,
DE = EF
5x = 3x + 4 (substitution)
Subtract 3x from each side
5x - 3x = 4
2x = 4
Divide both sides by 2
x = 2
DE = 5x
Plug in the value of x
DE = 5(2) = 10
EF = 3x + 4
Plug in the value of x
EF = 3(2) + 4 = 10
DF = DE + EF
DE = 10 + 10 (substitution)
DE = 20