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kirill [66]
3 years ago
8

Help with math homework please!

Mathematics
1 answer:
yuradex [85]3 years ago
8 0

The correct answer is:  [C}:  " 3 ⁻ ¹ " .

___________________________

<u>Note</u>:  " 3 =  3 ¹  " .

     →   "  3 ⁻ ¹  =  1 / (3 ¹)  = 1 /3 =  \frac{1}{3} " .

_______________________

Let us consider the remaining answer choices:

_______________________

Choice  [A}:  " ( - 1)³ " .    

<u>Note</u>:  " ( - 1)³ "  =  " { - 1 * - 1 * - 1 } " =  " -1 " .  

                →  " -1 " ≠ " \frac{1}{3} " .

                →  So; Choice  [A} is INCORRECT.

___________________________

Choice  [B]:  " (- 3)¹ " .

<u>Note</u>:  " ( - 3)¹ "  =  " -3 " .

                →  " -3 " ≠ " \frac{1}{3} " .

                →  So;  Choice  [B] is INCORRECT.

___________________________

    →  The correct answer is:  [C]: "  3 ⁻ ¹  . "

__________________________

Hope this was helpful!

Best of luck to you!

__________________________

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What is the sum of 5/8+3/10
FrozenT [24]
Change 5/8 and 3/10 so they have the same denominator

5/8×5/5=25/40

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A company has 125 personal computers. The probability that any one of them will require repair on a given day is 0.025. To find
Ostrovityanka [42]

Answer:

Binomial probability

P(X = 20) = C_{125,20}.(0.025)^{20}.(0.975)^{95}

Step-by-step explanation:

For each computer, there are only two possible outcomes. Either they fail, or they do not. The probability of a computer failing is independent from the probability of other computers failing. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 125, p = 0.025

To find the probability that exactly 20 of the computers will require repair on a given day, one will use what type of probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 20) = C_{125,20}.(0.025)^{20}.(0.975)^{95}

6 0
3 years ago
Three boys share $2100 in the ratio 3:5:7. Calculate how much each boy would get?
denis23 [38]

Answer:

3 +5+7 =15

3/15÷2100 =

5/15÷2100=

7/15÷2100=

you must do your own calculations

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