Ask question

Ask question

All categories

2 years ago

12

I need help w the answer

1 answer:

Semenov [28]2 years ago

8 0

Answer:

C

Step-by-step explanation:

Took the test and got it right hope it's right

You might be interested in

Find the value of x<br> 3+x/4=5

irakobra [83]

Step-by-step explanation:

it think it will help you

5 0

3 years ago

Read 2 more answers

Find the solution to the system of equations below (you can do this by substitution or elimination).

rewona [7]

Step-by-step explanation:

y=6+4x, as equation (iii)

=> -5x-(6+4x)=21

=> -5x-6-4x=21

=> -5x-4x-6=21

=> -9x-6=21

=> -9x=21+6

=> -9x=27

x= -3, by dividing both sides by -9

So, by inserting x in the first equation,

=> -4(-3)+y=6

=> 12+y=6

=> y=6-12

=> y= -6.

Therefore, x= -3 and y= -6

8 0

3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

or

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

3 years ago

The product of a number and four, increased by 5.

german

I’m pretty sure the answer is 4x+5

3 0

1 year ago

Read 2 more answers

There are 32 children in class 6B. On Thursday, four of the children were absent. What percentage of the children were absent on

Alex777 [14]

Answer:

8%

Step-by-step explanation:

32÷4=8

i hope this helps ^^

6 0

3 years ago

Read 2 more answers