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3 years ago

-8+9+5z+7x use z=3 and x=5

2 answers:

Ber [7]3 years ago

7 0

Your answer is 51 because you have to trade the 3 and the 5 out with the z and the x so to find your answer you add -8+9+5 then you *3 bc z=3 then you add 7 * 5 so you answer is 51

PolarNik [594]3 years ago

4 0

The answer is 51 bc if you multiply 7 and 5 you get 35 if you multiply 5 and 3 you get 15. so 15 plus 35 is 50 plus 9 and minus 8 you will get 51

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Given that sin0=21/29 what is the value cos 0 for 0°< 0<90°

sp2606 [1]

Answer:

20/29

Step-by-step explanation:

sin θ = 21/29

Use Pythagorean identity:

sin² θ + cos² θ = 1

(21/29)² + cos² θ = 1

441/841 + cos² θ = 1

cos² θ = 400/841

cos θ = ±20/29

Since 0° < θ < 90°, cos θ > 0. So cos θ = 20/29.

3 0

3 years ago

A bakery wants to determine how many trays of doughnuts it should prepare each day. Demand is normal with a mean of 5 trays and

Alexeev081 [22]

Answer:

4 trays should he prepared, if the owner wants a service level of at least 95%.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 5

Standard Deviation, σ = 1

We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(X > x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 5}{1})=0.95$

$= 1 -P( z \leq \displaystyle\frac{x - 5}{1})=0.95$

$=P( z \leq \displaystyle\frac{x - 5}{1})=0.05$

Calculation the value from standard normal z table, we have,

$\displaystyle\frac{x - 5}{1} = -1.645\\x = 3.355 \approx 4$

Hence, 4 trays should he prepared, if the owner wants a service level of at least 95%.

3 0

3 years ago

Find the distance between the points R(0,5) and S(12,3). round the answer to the nearest tenth

Burka [1]

12.2

((12) - (0))^2 + ((3) - (5))^2

5 0

3 years ago

Solve the following equations.<br> log2(x^2 − 16) − log^2(x − 4) = 1

Alenkasestr [34]

Answer:

$x=\frac{4*(2+e)}{e-2}$

Step-by-step explanation:

Let's rewrite the left side keeping in mind the next propierties:

$log(\frac{1}{x} )=-log(x)$

$log(x*y)=log(x)+log(y)$

Therefore:

$log(2*(x^{2} -16))+log(\frac{1}{(x-4)^{2} })=1\\ log(\frac{2*(x^{2} -16)}{(x-4)^{2}})=1$

Now, cancel logarithms by taking exp of both sides:

$e^{log(\frac{2*(x^{2} -16)}{(x-4)^{2}})} =e^{1} \\\frac{2*(x^{2} -16)}{(x-4)^{2}}=e$

Multiply both sides by $(x-4)^{2}$ and using distributive propierty:

$2x^{2} -32=16e-8ex+ex^{2}$

Substract $16e-8ex+ex^{2}$ from both sides and factoring:

$-(x-4)*(-8-4e-2x+ex)=0$

Multiply both sides by -1:

$(x-4)*(-8-4e-2x+ex)=0$

Split into two equations:

$x-4=0\hspace{3}or\hspace{3}-8-4e-2x+ex=0$

Solving for $x-4=0$

Add 4 to both sides:

$x=4$

Solving for $-8-4e-2x+ex=0$

Collect in terms of x and add $4e+8$ to both sides:

$x(e-2)=4e+8$

Divide both sides by e-2:

$x=\frac{4*(2+e)}{e-2}$

The solutions are:

$x=4\hspace{3}or\hspace{3}x=\frac{4*(2+e)}{e-2}$

If we evaluate x=4 in the original equation:

$log(0)-log(0)=1$

This is an absurd because log (x) is undefined for $x\leq 0$

If we evaluate $x=\frac{4*(2+e)}{e-2}$ in the original equation:

$log(2*((\frac{4e+8}{e-2})^2-16))-log((\frac{4e+8}{e-2}-4)^2)=1$

Which is correct, therefore the solution is:

$x=\frac{4*(2+e)}{e-2}$

6 0

4 years ago

Help&EXPLAIN <br> ==============

larisa86 [58]

Answer:

A = 108 in.²

Step-by-step explanation:

The figure can be decomposed into 3 rectangles.

✔️Area of rectangle 1 = L*W

L = 8 in.

W = 6 in.

Area = 8*6 = 48 in.²

✔️Area of rectangle 2 = L*W

L = 10 in.

W = 4 in.

Area = 10*4 = 40 in.²

✔️Area of rectangle 3 = L*W

L = 5 in.

W = 4 in.

Area = 5*4 = 20 in.

✔️Area of the irregular figure = 48 + 40 + 20 = 108 in.²

8 0

3 years ago