2 years ago

6/7 divided by 12/14

Mathematics

1 answer:

S_A_V [24]2 years ago

8 0

Answer:

Step-by-step explanation:

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Is 168/54 in simplest form?

Brut [27]

No, because both can be divided by two. in simplist form it is 3 1/9

6 0

3 years ago

, list the first five terms of each sequence, and identify them as arithmetic or geometric.

sveta [45]

Answer: -2, 2, 6, 10, 14

It is an Arithmetic sequence.

Step-by-step explanation:

Given Recursive formula : $A(n + 1) = A(n) + 4$ , for n ≥ 1 and A(1) = -2.

$A(2)=A(1 + 1) = A(1) + 4=-2+4=2$

$A(3)=A(2 + 1) = A(2) + 4=2+4=6$

$A(4)=A(3 + 1) = A(3) + 4=6+4=10$

$A(5)=A(4 + 1) = A(4) + 4=10+4=14$

Hence, the five terms of given sequence= -2, 2, 6, 10, 14

Since, there is common difference of 4 in two consecutive terms.

Therefore, it is an Arithmetic sequence.

5 0

3 years ago

Identify any outlier(s) in the data. {52, 61, 42, 46, 50, 51, 49, 44, 40, 66, 53, 67, 45, 64, 60, 69}

Kay [80]

There are none
For there to be a outlier there would need to be a number that is either around 74 or 34

6 0

3 years ago

For what values of a does the equation a+x= 1+xa^2 have no solution?

Anton [14]

Answer:

We have the equation

$a+x= 1+xa^2$

we leave the terms with x on the left side of the equation and the independent terms on the right side.

$x-xa^2=1-a\\(1-a^2)x=1-a\\$

resolving for x we have that

$x=\frac{1-a}{1-a^2}$

Since we need that the equation doesn't have solution, then it is necessary that the denominator of x be 0 and this occur when $1-a^2=0\\1=a^2\\a=\pm1$

Then, for $a=\pm1$ the equation hasn't solution

7 0

3 years ago

How to do this question plz answer

Soloha48 [4]

Answer:

(⌐■-■)

Step-by-step explanation:

Add perimeter of a quarter circle with radius 7 cm.

Hope this helps....

Have a nice day!!!!

3 0

3 years ago