Question

Given R(3, 7,-1),S(10,-4,0) find an ordered triple that represents RS and find the magnitude of RS.

Answer 1

Answer:

see explanation

Step-by-step explanation:

RS = s-r (s, r are the position vectors of R and S )

RS = (10, - 4, 0 ) - (3, 7, - 1) = (10 - 3, -4 - 7, 0 - (- 1)) = (7, - 11, 1 )

| RS | = $\sqrt{7^2+(-11)^2+1^2}$ = $\sqrt{171}$ = 3$\sqrt{19}$

Answer 2

Answer:

$| RS | =3\sqrt{19}$

Step-by-step explanation:

Given points are R ( 3 ,7, -1 ) and S (10 ,-4, 0)

The distance between R and S

RS = (10 ,-4, 0) - ( 3 ,7, -1 )

     = (10 - 3, -4 - 7, 0 - (- 1))

      = (7, - 11, 1 )

Magnitude is calculated as:

$| RS | =\sqrt{(7)^{2} + (-11)^{2} + (1)^{2}}$

$| RS | =\sqrt{49 + 121 + 1}$

$| RS | =\sqrt{171}$

$| RS | =3\sqrt{19}$