Question

What is the equation of a line perpendicular to y=1/4x+2 that passes through the point (0,1)

Answer 1

Answer: y = -4x + 1 or y = 1 - 4x

Step-by-step explanation:

First, we have to find the slope of the perpendicular. The slope of the line perpendicular to the other is the reciprocal and opposite value of the other line's slope.

This means that the slope perpendicular to y = 1/4x + 2 is -4, or -4/1.

Now we need to find the y-intercept, to do that we will use the equation y = mx + b. m = slope, b = y-intercept.

Plug in the values.

1 = -4(0) + b

Simplify.

1 = 0 + b

1 = b

Our y-intercept is 1.

Now we can form the slope-intercept equation for the line perpendicular to y = 1/4x + 2 that passes through the point (0, 1).

y = -4x + 1