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Gala2k [10]
2 years ago
5

What is the equation of a line perpendicular to y=1/4x+2 that passes through the point (0,1)

Mathematics
1 answer:
ipn [44]2 years ago
8 0

Answer: y = -4x + 1 or y = 1 - 4x

Step-by-step explanation:

First, we have to find the slope of the perpendicular. The slope of the line perpendicular to the other is the <u>reciprocal and opposite value</u> of the other line's slope.

This means that the slope perpendicular to y = 1/4x + 2 is -4, or -4/1.

Now we need to find the y-intercept, to do that we will use the equation y = mx + b. m = slope, b = y-intercept.

Plug in the values.

1 = -4(0) + b

Simplify.

1 = 0 + b

1 = b

Our y-intercept is 1.

Now we can form the slope-intercept equation for the line perpendicular to y = 1/4x + 2 that passes through the point (0, 1).

y = -4x + 1

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