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3 years ago

Spot eats of a can of dog food each day

Mathematics

1 answer:

Anit [1.1K]3 years ago

6 0

Answer:

$110

Step-by-step explanation:

First we would need to find out how many cans of dog food are required.

To find that you would divide 60 by 3.

60/3 = 20

You would then have to multiply that number by how much it costs for each pair of 3 cans, that being $5.50.

20 * 5.50 = $110

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What is 5.23 divided by 9

maks197457 [2]

0.581 i used a calculator

7 0

3 years ago

Read 2 more answers

What are the solutions of the equation (2x + 3)2 + 8(2x + 3) + 11 = 0

Tom [10]

Answer:

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

Step-by-step explanation:

The given equation is

$(2x+3)^2+8(2x+3)+11=0$

Let us treat this as a quadratic equation in $(2x+3)$ .

where $a=1,b=8,c=11$

The solution is given by the quadratic formula;

$(2x+3)=\frac{-b\pm \sqrt{b^2-4ac} }{2a}$

We substitute these values into the formula to obtain;

$(2x+3)=\frac{-8\pm \sqrt{8^2-4(1)(11)} }{2(1)}$

$(2x+3)=\frac{-8\pm \sqrt{64-44} }{2}$

$(2x+3)=\frac{-8\pm \sqrt{20} }{2}$

$(2x+3)=\frac{-8\pm2\sqrt{5} }{2}$

$(2x+3)=-4\pm \sqrt{5}$

$(2x+3)=-4-\sqrt{5}$ or $(2x+3)=-4+ \sqrt{5}$

$2x=-3-4-\sqrt{5}$ or $2x=-3-4+ \sqrt{5}$

$2x=-7-\sqrt{5}$ or $2x=-7+ \sqrt{5}$

$x=\frac{-7-\sqrt{5}}{2}$ or $x=\frac{-7+ \sqrt{5}}{2}$

5 0

4 years ago

Hayden decided to take martial arts classes at his local gym. He pays $35 each month for his membership and $12 for every class

gizmo_the_mogwai [7]

Hayden had the membership for one month and took 6 classes.

8 0

3 years ago

What is the cost of operating a 3.00-w electric clock for a year if the cost of electricity is $0.0900 per kw · h ?

brilliants [131]

We must take into account the following change of units:
$1kw = 1000w

1 year = 365 days

1 day = 24 hours$
Applying the change of units we have that the electric consumption for 1 year is given by:
$(3) * (1/1000) * (365) * (24) = 26.28 kw * h
$
Then, the total cost is given by:
$(26.28) * (0.0900) = 2.3652
$
Answer:
the cost of operating a 3.00-w electric clock for a year is:
$ 2.3652

8 0

3 years ago

Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have? Wh

svlad2 [7]

Let q and n represent the number of quarters and nickels respectively.

q=3n and .05n+.25q=1.6 These are the conditions in mathematical terms.

To solve, use the value of q from the first equation in the second equation to get:

.05n+.25(3n)=1.6 carry out indicated multiplication on left side

.05n+.75n=1.6 combine like terms on left side

.8n=1.6 divide both sides by .8

n=2, since q=3n

q=6

So Peggy had 2 nickels and 6 quarters.

3 0

3 years ago