<h3>
Answer:</h3>
(x, y) = (7, -5)
<h3>
Step-by-step explanation:</h3>
It generally works well to follow directions.
The matrix of coefficients is ...
![\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%264%5C%5C-5%263%5Cend%7Barray%7D%5Cright%5D)
Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...
![\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B26%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-4%5C%5C5%262%5Cend%7Barray%7D%5Cright%5D)
So the solution is the product of this and the vector of constants [-6, -50]. That product is ...
... x = (3·(-6) +(-4)(-50))/26 = 7
... y = (5·(-6) +2·(-50))/26 = -5
The solution using inverse matrices is ...
... (x, y) = (7, -5)
To find the x-intercept, substitute in
0
for
y
and solve for
x
. To find the y-intercept, substitute in
0
for
x
and solve for
y
.
x-intercept(s):
(
0
,
0
)
,
(
−
21
,
0
)
y-intercept(s):
(
0
,
0
)
Answer:
The greater number is 4π^2.
Step-by-step explanation:
1) 4π^2 = 39.4784176044
2)
= 31.304951685
4π^2 is greater.
In order find the Inequalities, First we need to Find the Equations of Both the Lines.
<u>Equation of First line :</u>
It is passing through the Points (0 , 2) and (4 , 0)
⇒ Slope = 
⇒ Equation of the First Line : 
⇒ Equation of the First Line : x + 2y = 4
<u>Equation of Second Line :</u>
It is passing through the Points (1.5 , 0) and (0 , -3)
⇒ Slope = 
⇒ Equation of the Second Line : y + 3 = 2x
⇒ Equation of the Second Line : 2x - y = 3
As the Shaded Area of the First Line is away from the Origin :
⇒ x + 2y ≥ 4
As the Shaded Area of the Second Line is towards the Origin and it is a Dotted line :
⇒ 2x - y < 3
So, the System of Linear Inequalities are :
⇒ x + 2y ≥ 4
⇒ 2x - y < 3