Of the 27 players trying out for the school basketball team, 8 are more than 6 feet tall and 7 have good aim. What is the probability that the coach would randomly pick a player over 6 feet tall or a player with a good aim? Assume that no players over 6 feet tall have good aim. A. 7/15 B. 6/15 C. 7/9 D. 5/9
The Answer Is
--------5/9--------
Answer:
32 m
Step-by-step explanation:
The distance across the river is give as x and we are interested in finding the value of x.
Both the triangles are similar by AA Postulate.
Therefore,
20/x = 10/16 (by c.s.s.t.)
2/x = 1/16
x = 16*2
x = 32 m
Answer:
just a guess I would say 70cm squared.
Answer:
y = 10x + 15
Step-by-step explanation:
you pick two points on the line
I picked (3,45) and (6,75)
you subtract the two x’s and y’s
75 - 45 = 30 (30 is the rise) you go up from 45 to 75
6 - 3 = 3 (you move 3 times to the right to get to the 6) so 3 is the run
slope = rise/run so 30/3 = 10
The y-intercept is the place you start on the graph so that is 15
Answer:
Step-by-step explanation:
We'll take this step by step. The equation is
![8-3\sqrt[5]{x^3}=-7](https://tex.z-dn.net/?f=8-3%5Csqrt%5B5%5D%7Bx%5E3%7D%3D-7)
Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time. First thing is to subtract 8 from both sides:
![-3\sqrt[5]{x^3}=-15](https://tex.z-dn.net/?f=-3%5Csqrt%5B5%5D%7Bx%5E3%7D%3D-15)
The goal is to isolate the term with the x in it, so that means that the -3 has to go. Divide it away on both sides:
![\sqrt[5]{x^3}=5](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%5E3%7D%3D5)
Let's rewrite that radical into exponential form:
If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:
On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely. On the right, let's rewrite that back in radical form to solve it easier:
![x=\sqrt[3]{5^5}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5E5%7D)
Let's group that radicad into groups of 3's now to make the simplifying easier:
![x=\sqrt[3]{5^3*5^2}](https://tex.z-dn.net/?f=x%3D%5Csqrt%5B3%5D%7B5%5E3%2A5%5E2%7D)
because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:
![x=5\sqrt[3]{5^2}](https://tex.z-dn.net/?f=x%3D5%5Csqrt%5B3%5D%7B5%5E2%7D)
which is the same as:
![x=5\sqrt[3]{25}](https://tex.z-dn.net/?f=x%3D5%5Csqrt%5B3%5D%7B25%7D)
