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Nikolay [14]
2 years ago
10

32% of 250 = ? I need help hurry!!

Mathematics
2 answers:
olga55 [171]2 years ago
8 0

Answer:

80

Step-by-step explanation:

Mnenie [13.5K]2 years ago
7 0

Answer:  80

Step-by-step explanation: pls mark my answer as brainlist

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A sample of 15 commuters in Chicago showed the average of the commuting times was 33.2 minutes. If s = 8.3 minutes, find the 95%
OleMash [197]

Answer:

The 95% confidence interval of the true mean.

(29.4261 ,36.9739)

Step-by-step explanation:

<u>Step :- (i)</u>

Given sample size 'n' =15

sample of the mean x⁻ = 33.2

The standard deviation of the sample 'S' = 8.3

<u>95% of confidence intervals</u>

<u></u>(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } ,x^{-} + t_{\alpha }\frac{S}{\sqrt{n} } )<u></u>

<u>Step:-(ii)</u>

<u>The degrees of freedom γ=n-1 = 15-1=14</u>

The tabulated value t = 1.761 at 0.05 level of significance.

now substitute all possible values, we get

(33.2 - 1.761\frac{8.3}{\sqrt{15} } ,33.2+ 1.761\frac{8}{\sqrt{15} } )

After calculation , we get

(33.2-3.7739 , 33.2+3.7739

(29.4261 ,36.9739)

<u>Conclusion</u>:-

the 95% confidence interval of the true mean.

(29.4261 ,36.9739)

8 0
3 years ago
Will someone please check my answers asap?? will give a brainliest
Usimov [2.4K]

Your choices are correct.

1. adding -3 to the function shifts its graph downward by 3 units.

2. 7^(2x) = (7^2)^x = 49^x

3. f(0) = -6; g(0) = -3, f(0) = 2×g(0)

3 0
3 years ago
A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu
Mars2501 [29]

Answer:

There can be at most 12 attendees in a corporate team-building event.

Step-by-step explanation:

Let x denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12

So, there can be at most 12 attendees in a corporate team-building event.

8 0
3 years ago
What is the difference between an irrational number and an integer? (PLZ HELP ME ANSWER ASAP!!!! All help is appreciated! :D)
enot [183]
So, first off it would help if you could define the terms irrational number and integer. Well, an irrational number is basically any real number that can't be expressed as a ratio of integers. They also cannot be represented by terminating or continuing decimals. And an integer is pretty much any number that cannot be written as a fraction or decimal, such as -2, 13, 257. It is not 2 and 1/2, or 4.75. Those would not be integers. Do you think you can figure out the difference?

8 0
3 years ago
Use the given x-values to identify solutions as ordered pairs to the equation y = −7x + 4 for x = 1, 3, 5, and 7
kolezko [41]
For x=1: -7 x 1 + 4 = -3     y=-3
The ordered pair:(1, -3)
for x=3: -7 x 3 + 4 = -17    y=-17
The ordered pair:(3, -17)
for x=5: -7 x 5 + 4 = -35    y=-35
The ordered pair:(5, -35)
for x=7: -7 x 7 + 4 = -45    y =-45
The ordered pair:(7, -45)
8 0
3 years ago
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