Answer:
1 and 4 has same pairs of solution.
Step-by-step explanation:
Solutions for the given equations are:
\begin{gathered}1. (x+6)(x - 6) = 0\\(x+6) = 0, (x-6) = 0\\x = -6, x = 6\\\\2. (x + 6)(x + 6) = 0\\(x+6) = 0, (x+6) = 0\\x = -6, x = -6\\\\3. (x - 6)(x - 6) = 0\\(x-6) = 0, (x-6) = 0\\x = 6, x = 6\\\\4. (2x + 12)(2x - 12) = 0\\(2x+12) = 0, (2x-12) = 0\\x = -6, x = 6\\\\5. (2x - 12)(x - 12) = 0\\(2x-12) = 0, (x-12) = 0\\x = 6, x = 12\\\\6. (x+12)(x - 12) = 0\\(x+12) = 0, (x-12) = 0\\x = -12, x = 12\\\\7. (x +12)(x-6) = 0\\(x+12) = 0, (x-6) = 0\\x = -12, x = 6\end{gathered}
1.(x+6)(x−6)=0
(x+6)=0,(x−6)=0
x=−6,x=6
2.(x+6)(x+6)=0
(x+6)=0,(x+6)=0
x=−6,x=−6
3.(x−6)(x−6)=0
(x−6)=0,(x−6)=0
x=6,x=6
4.(2x+12)(2x−12)=0
(2x+12)=0,(2x−12)=0
x=−6,x=6
5.(2x−12)(x−12)=0
(2x−12)=0,(x−12)=0
x=6,x=12
6.(x+12)(x−12)=0
(x+12)=0,(x−12)=0
x=−12,x=12
7.(x+12)(x−6)=0
(x+12)=0,(x−6)=0
x=−12,x=6
(x+6)(x - 6) = 0 and (2x + 12)(2x - 12) = 0 have same pair of solutions.
Step-by-step explanation:
there you go :)
Answer:
24 miles
Step-by-step explanation:
Distance formula (d):
D = sqrt[(x2 - x1)^2 + (y2 - y1)^2]
Home to library
(-4, 1) ; (-4, 9)
D1 = sqrt((-4 + 4)^2 + (9 - 1)^2)
D1 = 8
Library to park :
(-4, 9) ; (2, 1)
D1 = sqrt((2 + 4)^2 + (1 - 9)^2)
D3 = 10
Park to home :
(2, 1) ; (-4, 1)
D1 = sqrt((-4 - 2)^2 + (1 - 1)^2)
D2 = 6
Answer:
2. Both
3. e = 3, f = -5, g = 2
Step-by-step explanation:
2. Order doesn't affect product
3. You get e • f = -15, e • g = 6, f • g = -10 from the problem.
e = -15/f (solve for e)
(-15/f) • g = 6 (plug into second equation)
(-15g/f) = 6 (multiply)
-15g = 6f (multiply)
(-5g/2) = f (divide)
(-5g/2) • g = -10 (plug into last equation)
(-5g^2)/2 = -10 (multiply)
-5g^2 = -20 (mulitply)
g^2 = 4 (divide)
g = 2 (square root)
e • g = 6 (plug in for g, solve for e)
e • 2 = 6
e = 3
f • g = -10 (plug in for g, solve for f)
f • 2 = -10
f = -5
I don't know if your teacher made a typo because I tried this multiple times and got the same answer. I don't know how e is negative.
