The complete question is;
Lourdes is making a frame in the shape of a parallelogram. She adds diagonal braces to strengthen the frame. Parallelogram A B C D is shown. Diagonals are drawn from point A to point C and from point D to point B and intersect at point E. The length of D E is (3 y + 6) centimeters, the length of E B is (5 y minus 10) centimeters, and the length of E C is (2 y + 4) centimeters. How long is the brace that connects points B and D? 8 cm 16 cm 30 cm 60 cm
Answer:
60 cm. Option D is the correct answer
Step-by-step explanation:
From the image, the diagonals of the parallelogram bisect each other. Thus;
AE = EC and BE = ED
We are given that;
DE = 3y + 6 cm and BE = 5y - 10 cm, thus;
3y + 6 = 5y - 10
Rearranging, we have;
5y - 3y = 6 + 10
2y = 16
y = 16/2
y = 8 cm
The brace that bisects point B and D is BD. So, BD = BE + DE
So, BD = 5y - 10 + 3y + 6
BD = 8y - 4
Putting 8 for y to obtain;
BD = 8(8) - 4
BD = 64 - 4
BD = 60cm
ANSWER: 3.5, if both triangles are congruent then HJ should be the same length as AB.
Answer:

Step-by-step explanation:
We have to write an equation of a line which passes through the given point (-9,2) and is perpendicular to the given straight line y = 3x - 12 ........... (1)
Now, equation (1) is in the slope-intercept form and the slope of the line is 3.
Let, m is the slope of the required line.
So, 3m = -1
{Since, the product of the slopes of two perpendicular straight lines is -1}
⇒
Therefore, the equation of the required line in slope intercept form is
{Where c is a constant}
Now, this above equation passes through the point (-9,2) point.
So,
⇒ 2 = 3 + c
⇒ c = - 1
Therefore, the equation of the required straight line is
(Answer)