All categories

3 years ago

Plz help I need help

Mathematics

2 answers:

valentina_108 [34]3 years ago

8 0

Answer:

Step-by-step explanation:

solve:

5/2 ÷ 1/4

calculate the result:

5/2 × 4 = 10

Pani-rosa [81]3 years ago

4 0

The answer is -7! hope this helps

You might be interested in

the arithmetic sequence a sub i is defined by the formula a sub 1 =-4910 a sub i-1 +8 find the sum of the first 575 terms in the

maks197457 [2]

Answer:

Step-by-step explanation:

3 0

3 years ago

PLEASE HELP! THIS IS DUE RN AND I CAN'T FIGURE IT OUT! I WILL AWARD BRAINLIEST TO THE CORRECT ANSWER!!

Nataliya [291]

Answer:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Exact Form:√133

Decimal Form:

11.53256259…

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Thomas lives 350 miles from the beach. He drives to the beach at an average rate of 50 miles per hour. Use that information and

sweet-ann [11.9K]

Answer:

Step-by-step explanation:

use the equation: y =50x-350 where x is the number of hours driving

hrs

1 50 300

2 100 250

3 150 200

5 250 100

7 350 0

4 0

3 years ago

I will give you brainliest if you right down the answer and explain it

liberstina [14]

to find the mid point,

m=-2+1/2,-5+3/2

=-1/2,-1

8 0

3 years ago

Consider this right triangle. 21 29 20 Enter the ratio equivalent to s

AleksAgata [21]

Answer:

Part 1) $sin(B)=\frac{21}{29}$

Part 2) $csc(A)=\frac{29}{20}$

Part 3) $cot(A)=\frac{21}{20}$

Step-by-step explanation:

The complete question is

Consider this right triangle. 21 29 20 Write the ratio equivalent to: Sin B - CscA- Cot B

The picture of the question in the attached figure

Part 1) Write the ratio equivalent to: Sin B

we know that

In the right triangle ABC

$sin(B)=\frac{AC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(B)=\frac{21}{29}$

Part 2) Write the ratio equivalent to: Csc A

we know that

In the right triangle ABC

$csc(A)=\frac{1}{sin(A)}$

$sin(A)=\frac{BC}{AB}$ -----> by SOH (opposite side divided by the hypotenuse)

substitute the values

$sin(A)=\frac{20}{29}$

therefore

$csc(A)=\frac{29}{20}$

Part 3) Write the ratio equivalent to: Cot A

we know that

In the right triangle ABC

$cot(A)=\frac{1}{tan(A)}$

$tan(A)=\frac{BC}{AC}$ -----> by TOA (opposite side divided by the adjacent side)

substitute the values

$tan(A)=\frac{20}{21}$

therefore

$cot(A)=\frac{21}{20}$

4 0

3 years ago