Answer:
volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( 
x + b )² dx
Step-by-step explanation:
Given the data in the question and as illustrated in the image below;
R is in the region first quadrant with vertices; 0(0,0), A(a,0) and B(0,b)
from the image;
the equation of AB will be;
y-b / b-0 = x-0 / 0-a
(y-b)(0-a) = (b-0)(x-0)
0 - ay -0 + ba = bx - 0 - 0 + 0
-ay + ba = bx
ay = -bx + ba
divide through by a
y = x + ba/a
y = x + b
so R is bounded by y = x + b and y =0, 0 ≤ x ≤ a
The volume of the solid revolving R about x axis is;
dv = Area × thickness
= π( Radius)² dx
= π ( x + b )² dx
V = π ₀∫^a ( x + b )² dx
Therefore, volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a ( x + b )² dx
If a cup is a regular sized cup that is 2 deciliters, and 1 liter equals 10 deciliters, that means that 1 liter = 5 cups, which means that 3 liters = 15 cups. If it is a cup that has 0.33 dl, then the correct number would be 9 cups.
Answer:
(A) x=-28
Step-by-step explanation:
237 -6x = 405 [note that 6*(-x) is (-6x)]
-6x = 168 [subtract 237 from both sides]
x = -28 [divide both sides by (-6)]
26, 24, 28 could be the answer
First, you need convert the decimals into fraction
0.26 = 26/100 = 13/50
The next step would be drawing 50 small boxes on a piece of paper. Make it colorless.
The final stap would be giving 13 out of those 50 boxes with different color (such as black), and you're done
