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Nastasia [14]
3 years ago
12

California has 143deaths from heart disease and 137deaths from cancer per100,000 residents. Which rate is more extreme compared

to other states? A.Perform any needed computations here: b. Is California's rate for heart disease or for cancer more extreme compared to the other states? Explain:
Mathematics
1 answer:
belka [17]3 years ago
3 0

Answer:

California's rate for heart disease is more extreme than Cancer

Step-by-step explanation:

Given

Represent Cancer with C and Heart Disease with H

H = 143

C = 137

Population = per 100,000

First we need to determine the probability of both.

For H

P(H) = H/100000

P(H) = 143/100000

P(H) = 0.00143

For C

P(C) = C/100000

P(C) = 137/100000

P(C) = 0.00137

By comparison,

0.00143 > 0.00137

So, California's rate for heart disease is more extreme than Cancer.

Reason: P(H) > P(C)

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The population of a particular city is given by the function P(t) = 27,400(1.07)t, where t is the time in years and P(t) is the
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Answer:

27,400 is the current population

7% is the rate of increase

The new size is:

  • 38,430 is the population if t is an exponent
  • 146,590 is t is NOT an exponent in the formula you typed

Step-by-step explanation:

To find the population in a future year, use the formula:

P(t) = 27,400(1.07)t

Substitute the value t=5 to find the population in 5 years.

P(t) = 27,400(1.07)t\\P(t) = 27,400(1.07)(5)\\P(t) = 146,590


Or if the equation is supposed to have t as an exponent then look below:

P(t) = 27,400(1.07)^t

Substitute the value t=5 to find the population in 5 years.

P(t) = 27,400(1.07)^t\\P(t) = 27,400(1.07)^(5)\\P(t) = 38,430

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A_0 is the starting population which is 27,400 here.

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