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Harlamova29_29 [7]
2 years ago
10

.............. 1010111 needs to be transferred w.ith odd parity and the answer is

Computers and Technology
2 answers:
notsponge [240]2 years ago
7 0

Answer:

A. 01010111

Explanation:

This is because in odd parity, the number on the far left (the 8th number) would always be a 0

katrin [286]2 years ago
4 0
A! your answer is A- 01010111
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Given the following adjacency matrix, what is the approximate rank vector after one iteration of the power iteration method (use
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Note: The matrix referred to in the question is: M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

Answer:

a) [5/18, 5/18, 4/9]'

Explanation:

The adjacency matrix is  M = \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]

To start the power iteration, let us start with an initial non zero approximation,

X_o = \left[\begin{array}{ccc}1\\1\\1\end{array}\right]

To get the rank vector for the first Iteration:

X_1 = MX_0

X_1 =  \left[\begin{array}{ccc}1/2&1/3&0\\1/2&1/3&0\\0&1/3&1\end{array}\right]\left[\begin{array}{ccc}1\\1\\1\end{array}\right] \\\\X_1 = \left[\begin{array}{ccc}5/6\\5/6\\4/3\end{array}\right]\\

Multiplying the above matrix by 1/3

X_1 = \left[\begin{array}{ccc}5/18\\5/18\\4/9\end{array}\right]

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