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GarryVolchara [31]
3 years ago
13

Assume you want to write a code to calculate the addition of two numbers digit by digit. Provide the running time for your algor

ithm, assuming the inputs are two n-digit numbers. Explain your answer
Computers and Technology
1 answer:
Sergio039 [100]3 years ago
5 0

Answer:

Explanation:

Using Python programming language

Explanation:

1. I defined a function add and passed in two parameters (a,b).

2. In the block of the function, I added the two numbers and printed the result.

3. I decided to use a function so that the program is re-usable and can accept various inputs.

Find the code below. (# are used for comments)

#Addition of numbers

def add(a,b):

   print(a+b)

#Test Cases

add(2,4.5)      #Result=6.5

add(10,290)     #Result=300

add(2.567,4.58) #Result=7.147

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What is an 8086 microprocessor used for
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A sixteen bit microprocessor chip used in early IBM PCs. The Intel 8088 was a version with an eight-bit externaldata bus.

The Intel 8086 was based on the design of the Intel 8080 <span>and </span>Intel 8085 (it was source compatible with the 8080)with a similar register set, but was expanded to 16 bits. The Bus Interface Unit fed the instruction stream to theExecution Unit through a 6 byte prefetch queue, so fetch and execution were concurrent - a primitive form ofpipelining (8086 instructions varied from 1 to 4 bytes).

It featured four 16-bit general registers, which could also be accessed as eight 8-bit registers, and four 16-bit indexregisters (including the stack pointer). The data registers were often used implicitly by instructions, complicatingregister allocation for temporary values. It featured 64K 8-bit I/O (or 32K 16 bit) ports and fixed vectored interrupts.There were also four segment registers that could be set from index registers.

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Although this was largely acceptable for assembly language, where control of the segments was complete (it couldeven be useful then), in higher level languages it caused constant confusion (e.g. near/far pointers). Even worse, thismade expanding the address space to more than 1 meg difficult. A later version, the Intel 80386, expanded thedesign to 32 bits, and "fixed" the segmentation, but required extra modes (suppressing the new features) forcompatibility, and retains the awkward architecture. In fact, with the right assembler, code written for the 8008 canstill be run on the most <span>recent </span>Intel 486.

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Other factors were the 8-bit Intel 8088 version, which could use existing Intel 8085-type components, and allowed the computer to be based on a modified 8085 design. 68000 components were not widely available, though it could useMotorola 6800 components to an <span>extent.
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Read 2 more answers
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quester [9]

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