The equivalence

means that n-5 is a multiple of 12.
that is
n-5=12k, for some integer k
and so
n=12k+5
for k=-1, n=-12+5=-7
for k= 0, n=0+5=5 (the first positive integer n, is for k=0)
we solve 5000=12k+5 to find the last k
12k=5000-5=4995
k=4995/12=416.25
so check k = 415, 416, 417 to be sure we have the right k:
n=12k+5=12*415+5=4985
n=12k+5=12*416+5=4997
n=12k+5=12*417+5=5009
The last k which produces n<5000 is 416
For all k∈{0, 1, 2, 3, ....416}, n is a positive integer from 1 to 5000,
thus there are 417 integers n satisfying the congruence.
Answer: 417
Answer:
I think the answer would be 22.15 but I'm not really sure.
Answer:

Step-by-step explanation:
Please find the attachment.
Let us divide our given image in several parts and then we will find area of different parts.
First of all let us find the area of our red rectangle with side lengths 6 units and 7 units.



Now let us find area of yellow triangle on the top of red rectangle. We can see that base of triangle is 6 units and height is 1 unit.



Let us find the area of green triangle.


Now we will find the area of blue triangle, whose base is 6 units and height is 2 units.


Let us add all these areas to find the area of our figure.



Therefore, area of our given figure is 54 square units.
Answer:
-2
Step-by-step explanation:
x + 3 = -(x + 1)
open the bracket
x + 3 = -x -1
x+x= -1-3
2x= -4
X = -4/2= -2
Answer:
4b^2+2b (b^2 means b squared)
Step-by-step explanation: