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3 years ago

15

Harvard university accepts 6 students for every100 applicants how many students will be accepted if 850 applicants apply for adm

ission

1 answer:

Nuetrik [128]3 years ago

7 0

6/100 * 850 = 51 students.

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A marketing consultant observed 40 consecutive shoppers to estimate the average money spent by shoppers in a supermarket store.

KonstantinChe [14]

Answer:

0.998 is the probability that the average money spent by a sample of 40 shoppers is within $10 of the actual population mean.

Step-by-step explanation:

We are given the following information in the question:

Standard Deviation, σ = $21.51

We are given that the distribution of average money spend is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

We have to find:

P( average money spent is within $10 of the actual population mean.)

$= P( z \leq \displaystyle\frac{10\times \sqrt{40}}{21.51}}) = P(z \leq 2.94)$

Calculation the value from standard normal z table, we have,

$P(z \leq 2.94) = 0.998$

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2 years ago

Which of the following values could the number 500,000 be composed of?

OverLord2011 [107]

50000 tens

5000hundreds

How?

1ten=10

50000 tens:-

$\\ \sf\longmapsto 50000(10)=500000$

1hundred=100

5000hundreds

$\\ \sf\longmapsto 5000(100)=500000$

8 0

2 years ago

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The slope of the line segment above is<br><br> True<br> False

jolli1 [7]

Answer:False

Step-by-step explanation:

Because when you go up and you subtract that numbers you don't get the number you need

7 0

2 years ago

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Answer to the best of your abilities, pls & ty !

klemol [59]

Answer:

54

Step-by-step explanation:

Por ejemplo, baile

Solamente tres estudiantes siempre lo practican.

4 0

2 years ago

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Lines e and f are parallel. The mAngle9 = 80° and mAngle5 = 55°. Parallel lines e and f are cut by transversal c and d. All angl

brilliants [131]

Answer:

$(A)m\angle 2=125^\circ\\(C)m\angle 8=55^\circ\\(E)m\angle 14=100^\circ$

Step-by-step explanation:

The diagram of the problem is drawn and attached.

Given that:

$m\angle 9 =80^\circ\\m\angle 5 =55^\circ$

$m\angle 5+ m\angle 6=180^\circ\\55^\circ+ m\angle 6=180^\circ\\m\angle 6=180^\circ-55^\circ\\m\angle 6=125^\circ\\$Now:\\m\angle 6 = m\angle 2 $(Corresponging angles)\\Therefore m\angle 2=125^\circ\\$

$m\angle 5= m\angle 8=55^\circ $(Vertically Opposite Angles)$

Also

$m\angle 9+ m\angle 10=180^\circ\\80^\circ+ m\angle 10=180^\circ\\m\angle 10=180^\circ-80^\circ\\m\angle 10=100^\circ\\$Now:\\m\angle 10 = m\angle 14 $(Corresponging angles)\\Therefore m\angle 14=100^\circ\\$

4 0

3 years ago

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