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SCORPION-xisa [38]
3 years ago
8

The sum of three consecutive odd numbers is 33. What is the smallest of these numbers?

Mathematics
1 answer:
Anna007 [38]3 years ago
7 0
9, 11, 13 are the theee consecutive off numbers and the smallest is 9.
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Given that y varies directly as x and inversely 2m-1 and that y=5 when x-7 and m=4 .
Sergeu [11.5K]

Answer:

Step-by-step explanation:

y ∞ x/m

y = kx/m

Where k is the constant of proportionality

A. k = ym/x

y=5 when x=7 and m=4

k = (5×4)/7

k = 20/7

y = 20x/7m

B)the value of when x=2and m=2

y = 20x/7m

y = (20×2)/(7×2)

y = 40/14

y = 20/7

y = 2 6/7

C. The value of m when y=2 and x=4

y = 20x/7m

7ym = 20x

m = 20x/7y

m = (20×4)/(7×2)

m = 80/14

m = 40/7

m = 5 5/7

3 0
3 years ago
10 points
Tpy6a [65]

Answer:

a) 0.048 = 4.8% probability of exactly seven successes.

b) 100% probability of at least twenty-two successes.

Step-by-step explanation:

The first question we use the binomial distribution, while for the second we use the approximation to the normal.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

Question a:

Here, we have n = 10, p = 0.41.

This probability is P(X = 7). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 7) = C_{10,7}.(0.41)^{7}.(0.59)^{3} = 0.048

0.048 = 4.8% probability of exactly seven successes.

b) With 150 trials and a 39 chance of success, the probability of at least twenty-two successes.

Here we have n = 150, p = 0.39

Mean and standard deviation:

\mu = 150*0.39 = 58.5

\sigma = \sqrt{150*0.39*0.61} = 5.9737

This probability is, using continuity correction, P(X \geq 22 - 0.5) = P(X \geq 21.5), which is 1 subtracted by the p-value of Z when X = 21.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{21.5 - 58.5}{5.9737}

Z = -6.19

Z = -6.19 has a p-value of 0

1 - 0 = 1

100% probability of at least twenty-two successes.

5 0
3 years ago
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Kisachek [45]

Answer:

A,c,e is correct. “A number cubed” is a power, where the base is the variable, n, and the exponent is 3, “A number cubed” is a power where the base is 3 and the exponent is n and The expression is written as n3+4

Step-by-step explanation:

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find the length and the breadth of a rectangular plot whose area is 660 sq.m and its perimeter is 104​
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find the mean median mean devialion

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