Answer:
y(-4) = 5
y'(-4) = -7
Step-by-step explanation:
Hi!
Since the tangent line T and the curve y must coincide at x=-4
y(-4) = T(-4) = 5
On the other hand, the derivative of the curve evaluated at -4 y'(x=-4) must be the slope of the tangent line. Which inspecting the tangent line T(x) is -7
That is:
y'(-4) = -7
k = 5
the equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
To obtain this form use the method of completing the square
Since the coefficient of the x² term is 1 then
add/ subtract (half the coefficient of the x-term )² to x² - 6x
f(x) = x² + 2(- 3)x + 9 - 9 + 14 = (x - 3)² + 5 → k = 5
The very first one probably
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Answer:
The student got 34 of the 40 questions correct.
Step-by-step explanation:
85% of 40 is 34.
Hope this helps! :)
I would appreciate brainliest, if not that's okay!
