Calculate the hypotenuse( h ) using Pythagoras' identity
h =√(4² + 7²) = √(16 + 49) = √65
sinΘ = 4 / √65 ⇒ cscθ = √65 / 4
cosθ = 7/ √65 ⇒ secθ = √65 / 7
tanθ =
⇒ cotθ = 
I wanna say it’s letter f or j I’m not sure.
Step-by-step explanation:
3x2 -5x+1=0
Quadratic eq ax2 +bx+c=0
Discriminant=b2 -4ac
=(-5)2 -4*3*1
=25-12
=13>0 so 2 solutions.
Factorise to get (x - 0.5)^3 = 0
The equation has root 1/2 with multiplicity 3.