V=B+15
V+2B=180
Therefore:
3B+15=180
B=55
V=70
Check:
V+2B=180
70+2(55)=180
70+110=180
180=180. Checks.
Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
Answer:
boys = 705
girls = 783
Step-by-step explanation:
We are to find the number of boys and girls in the school
the answer can be determined using simultaneous equation
x = boys
y = girls
y - x = 78 equation 1
y + x = 1488 equation 2
subtract equation 1 from 2
2x = 1410
x = 1410/2 = 705
Substitute for x in equation 1
y - 705 = 78
y = 705 + 78 = 783
Let, that fraction = x
So, 8 * x = 5
x = 5/8
In short, Your Answer would be 5/8
Hope this helps!